OK I'm having a little trouble with my maths homework and since there are some real talented programmers on this forum I figured one of you could help me Find the following Integral: Any help would be appreciated, thanks
Pretty Simple. 1.Integrate 3 separately. 2.Take x common outside. 3.That leaves x(raised to minus power half) + 6x(raised to power too ie. squared) The x that was taken common gets cancelled with the denominator. 4. Answer- 3x + logx + 2x(cube) .....most probably. The answer may/ may not be correct(coz it's all mental math here ) , BUT I'm dead sure about the first 3 steps If you know even 1/4th of integration, you'd be able to make head and tail of what i said.
Hmmm Thanks! I'll have to check this with my maths teacher though =D I'm pretty sure he'll call me an idiot for not knowing the answer to this though since we just went over it today! Out of all the other subjects, why did I pick maths? =[
EASY QUESTION! I LOVE THIS SORTA PROBLEMS <> Integrate 3 .. which would be 3x + <> integrate (root x) / x which when simplified becomes = 1/(root x) which integrates to = 2.(root x) + <> integrate (6x^3)/x , which when simplified gives = 6.x^2...which integrates to = [6.(x^3)]/3 = 2.(x^3) + DONT FORGET TO ADD '+c' ps: too lazy to check all those steps up there...but the idea is correct