I got a code beginning: var _0x5e8f=[ Code (JavaScript): I used hex decoded and have this result : http://ddecode.com/hexdecoder/?results=2333a7c3dd787926fb774185401a84ac but I can't decoded this code in result beginning with var _0x5e8f=["d=['.hX Code (JavaScript): please help me,is it possible to decrypt this?
16 views and zero replay please help me and this another code: eval(function (_0x383fx1,_0x383fx2,_0x383fx3,_0x383fx4,_0x383fx5,_0x383fx6){_0x383fx5=function (_0x383fx3){return (_0x383fx3<_0x383fx2?_0x5e8f[4]:_0x383fx5(parseInt(_0x383fx3/_0x383fx2)))+((_0x383fx3=_0x383fx3%_0x383fx2)>35?String[_0x5e8f[5]](_0x383fx3+29):_0x383fx3.toString(36));} ;if(!_0x5e8f[4][_0x5e8f[6]](/^/,String)){while(_0x383fx3--){_0x383fx6[_0x383fx5(_0x383fx3)]=_0x383fx4[_0x383fx3]||_0x383fx5(_0x383fx3);} ;_0x383fx4=[function (_0x383fx5){return _0x383fx6[_0x383fx5];} ];_0x383fx5=function (){return _0x5e8f[7];} ;_0x383fx3=1;} ;while(_0x383fx3--){if(_0x383fx4[_0x383fx3]){_0x383fx1=_0x383fx1[_0x5e8f[6]]( new RegExp(_0x5e8f[8]+_0x383fx5(_0x383fx3)+_0x5e8f[8],_0x5e8f[9]),_0x383fx4[_0x383fx3]);} ;} ;return _0x383fx1;} (_0x5e8f[0],62,3657,_0x5e8f[3][_0x5e8f[2]](_0x5e8f[1]),0,{})); Code (JavaScript):
It's encoded for a reason. The original developer obviously didn't want someone seeing the source code because they didn't want people ripping their hard work. The fact you are having to attempt to reveal the source code suggests you are unable to purchase the original source code so I'm not going to help you. I guess if you want it that bad you are going to have to learn how to use JavaScript properly. This should help you get started: https://www.google.co.uk/search?hl=...gws_rd=ssl#hl=en-GB&q=how+to+write+javascript Thanks
It's also likely those numbers are just random offsets into another array somewhere, or just a incremented value from the encoder, meaning they DON'T decode into anything meaningful; on purpose, that's part of the encoding; it's mono-directional as it just replaces the meaningful function names with a random numbered value.