Need Help with Object Oriented PHP

classfile.php
==============

class myclass {
public myvar1;
public myvar2;

function __construct() {
   if ($his->myvar1 == "a") {
       $this->myvar2 = "A";
   } else {
       $this->myvar2 = "B";
   }
}


   function show_var() {
      return $this->myvar2;
   }

}

Code (markup):

index.php
===========

include("classfile.php");
$mytest = new myclass();
$mytest->myvar1 = "a";

echo $mytest->myvar1;   // Result a
echo $mytest->myvar2;   // [COLOR="red"]Result B[/COLOR]

Code (markup):

Question
=========

Why Im getting a result of "B" for $this->myvar2?
I should get A since Ive modified the value of myvar1 to "a" in my index.php file and based on the condition if myvar1 = "a" myvar2 should return a value of "A".

 

The code you have posted has 3 parsing errors:
line public myvar1; should have been: public $myvar1;
line public myvar2; should have been: public $myvar2;
line if ($his->myvar1 == "a") should have been if ($this->myvar1 == "a")

after correcting the code it does what you say it does. That's because the constructor is only called once when the object $mytest is created (in this line: $mytest = new myclass(); )
Your script modifies the value of myvar2 afterwords but this does not affect myvar2 in any way.

 

So how can I modify the value of myvar1 to "a" from my index.php so that myvar2 will give me a value of "A".

 

<?php
class myclass
	{
	public $myvar1;
	public $myvar2;

	function __construct($init_val)
		{
		$this->myvar1=$init_val;
		
		if ($this->myvar1 == "a")
			$this->myvar2 = "A";
		else
			$this->myvar2 = "B";
		}


   function show_var() 
		{
      	return $this->myvar2;
   		}
	}

$mytest = new myclass("a");

echo $mytest->myvar1;   // Result a
echo $mytest->myvar2;   // Result A
?>

PHP:

 

meaning if I need to change / pass multiple variables

Ill do it this way

function __construct($init_val1, $init_val2, $init_val3)
...

$mytest = new myclass("a", "b", "c");

Code (markup):

Cant I not do it something like this

$init_val1 = "a"
$init_val1 = "b"
$init_val1 = "c"

Code (markup):

 

because you are calling

function show_var() {
return $this->myvar2;
}

thats why you are getting this value.