need help with array

hello there, this is my command

<?php

 $allowed_refferer = array(
  'http://www.google.com',
  'http://www.yahoo.com'
 );

 if (in_array($_SERVER['HTTP_REFERER'], $allowed_refferer)) {
  echo 'a';
 } else {
  echo 'b';
 }

?>

PHP:

i have one problem hope someone can help me with this...
if the refferer is http://www.google.com is show me echo a

but if the refferer is http://www.google.com/search... is not working anymore ... how i can make this work ?

i want to use array becouse is more easy to add the links becouse before i use preg_match ...

 

Hmm I don't get it what's the problem. If the referrer is from http://www.google.com/search then why not just include it in the array? Otherwise, use preg_match

<?php

 $allowed_refferer = array(
  'http://www.google.com',
  'http://www.yahoo.com',
  'http://www.google.com/search'
 );

 if (in_array($_SERVER['HTTP_REFERER'], $allowed_refferer)) {
  echo 'a';
 } else {
  echo 'b';
 }

?>

PHP:

 

Would be easier to do it by host rather than URL:

if( isset( $_SERVER['HTTP_REFERER'] ) ) {
	$Referer = parse_url( $_SERVER['HTTP_REFERER'] );

	 $allowed_refferer = array(
	  'google.com',
	  'yahoo.com'
	 );

	 if (in_array( $Referer['host'] , $allowed_refferer)) {
	  echo 'a';
	 } else {
	  echo 'b';
	 }
}

PHP:

 

One other note, in_array() is case sensitive, so you might want to use strtolower().