MySQL warning error! Help me!

I hve doing a poll script in PHP and all is working perfectly, but only it has this error when I sent my vote, and do not know how to solve:

Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in /home/u7/web/html/index/encuesta.php on line 9

PHPCode is:

include('db.php');
$opciones = array ('DJ-ERR0R-','DJ-Ray','DJ-AdituS','DJ-Lydi','DJ-L3y');
if(isset($_GET["voto"])){
   $ip = $REMOTE_ADDR;
   $sql ="INSERT INTO encuesta (ip,voto) VALUES ('$ip',".$_GET["voto"].")";
LINE OF ERROR->   $votos = mysql_result(mysql_query($sql),0);  
}
$i = 0;
$sql ="SELECT count(ip) FROM encuesta";
$total = mysql_result(mysql_query($sql),0); 
echo "<form><table border=\"0\" cellpadding=\"0\" cellspacing=\"0\">\n";
while ($opciones[$i]){
   $sql ="SELECT count(ip) FROM encuesta WHERE voto = $i";
   $votos = mysql_result(mysql_query($sql),0);
   @$porcentaje = round($votos/$total*100,2);
   echo "  <tr>\n";
   echo "    <td colspan=\"3\"><b>$opciones[$i]</b></td>\n";
   echo "  </tr>\n";
   echo "  <tr>\n";
   echo "    <td><input type=\"radio\" value=\"$i\" name=\"voto\"></td>\n";
   echo "    <td><hr color=\"blue\" size=\"10\" width=\"$porcentaje\" align=\"left\">\n";
   echo "    </td>\n";
   echo "    <td align=\"right\">$porcentaje% ($votos)</td>\n";
   echo "  </tr>\n";
   $i++;
}
echo "  <tr>\n";
echo "    <td colspan=\"3\"><br><input type=\"submit\" value=\"Votar\"></td>\n";
echo "  </tr>\n";
echo "</table></form>";

PHP:

 

That error message means that you aren't properly connected to MySQL. Your real issue is with mysql_connect in db.php.

 

No, it's not the problem! Please somebody that may help me!

 

Thats some confusing PHP coding right there. What exactly are you trying to do?

 

I did that script and is working correctly, but when somebody send vote, it get mysql error on line 9. Get up and read my first post of this thread.

 

If somebody can leave good help, please do it.