MySQL Error

$connection = mysql_connect('localhost',$user,$pass);
  mysql_select_db($dbname, $connection);
  $vault_id = mysql_real_escape_string( $vault_id );
  $combo = mysql_real_escape_string( $combo );
  $var = "SELECT * FROM Vaults WHERE Vault_ID='". $vault_id . "'";
  $result = mysql_query($var , $connection);

  while($row = mysql_fetch_array($result))
   {
    if($row['Vault_ID'] == $vault_id && $row['Combo'] == $combo)
     {
      $var = "SELECT Contents FROM Vaults WHERE Vault_ID='". $vault_id . "'";
      $return = mysql_query($var , $connection);
      return $return;
     }
    else
     {
      return 'FALSE';
     }
   }

Code (markup):

What I am trying to do is find out if the variable $vault_id and $combo correspondingly match up with two columns Vault_ID and Combo both in the same row. If not it returns false. Otherwise it gets the value of the contents column in that same row. For example:

Vault_ID | Combo | Contents
----------------------------------
01234 01-01-01 Vault Contents
12345 02-02-02 More Contents

If my $vault_id == '01234' and $combo == '01-01-01' then it would return "Vault Contents" or if $vault_id == '12345' and $combo == '02-02-02' it would return "More Contents" otherwise it returns false.

However it doesn't do this at all. It doesn't return a MySQL error but my host is weird about PHP/MySQL errors so there may be one I am not sure. Do you guys see an error or a mistake I made in syntax. Thanks for at least reading this and attempting to help me.

 

"SELECT Contents FROM Vaults WHERE Vault_ID = '".$vault_id."' AND Combo = '".$combo."'";

 

:\ Still doesn't return anything. Thanks for trying to help though!