mySQL 4.1.22 - JOIN problem

Discussion in 'MySQL' started by gfreeman, Feb 10, 2008.

  1. #1
    I have two tables, players and squads

    All players are in the players table, but only some of them are in the squads table. I am trying to produce a list of players that are on the same club, but not in the squads table

    
    mysql> SELECT * FROM players
    +----------+--------+--------------+
    | playerID | name   | playerClubID |
    +----------+--------+--------------+
    | 1        | Smith  | 100          |
    | 2        | Brown  | 100          |
    | 3        | Jones  | 100          |
    | 4        | Black  | 101          |
    | 5        | White  | 101          |
    +----------+--------+--------------+
    
    mysql> SELECT * FROM squads
    +------------+-------+----------+
    | sqPlayerID | name  | sqClubID |
    +------------+-------+----------+
    | 2          | Brown | 100      |
    | 4          | Black | 101      |
    +------------+-------+----------+
    
    mysql> SELECT * FROM players INNER JOIN squads 
    ON players.playerClubID = squads.sqClubID AND 
    players.playerClubID = 100 AND 
    players.playerID <> squads.squadID ORDER BY 
    players.playerID
    
    [I]DOES NOT PRODUCE ....[/I]
    +----------+-------+--------------+
    | playerID | name  | playerClubID |
    +----------+-------+--------------+
    | 1        | Smith | 100          |
    | 3        | Jones | 100          |
    +----------+-------+--------------+
    Code (markup):

    What mySQL command would produce a list of entries from the players table with a specific playerClubID who are not in the squad table?
     
    gfreeman, Feb 10, 2008 IP
  2. AstarothSolutions

    AstarothSolutions Peon

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    #2
    What you want is:
    
    SELECT * 
    FROM Players LEFT OUTER JOIN 
    Squads ON Players.PlayerID = Squads.sqplayerID 
    WHERE Players.PlayerClubID = 100 AND Squads.sqplayerID is null;
    Code (SQL):
     
    AstarothSolutions, Feb 10, 2008 IP
  3. gfreeman

    gfreeman Peon

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    #3
    \o/

    yay!

    That works perfectly!

    Thank you SO much!
     
    gfreeman, Feb 10, 2008 IP