How to get multiple color codes together as background in a Header? <tr> <td width="770" height="22" body bgcolor="#F6AD8A,#CCCCCC,#FFDD6C,#CCCCDA></td> </tr>
I don't think that's too possible, unless you specify where you want each colour. This can be done using CSS:
Gradients are one of the top design features of "Web 2.0" sites and since I see gradients on many newer sites I'll have to agree. Gradients are often used as the background for buttons, header images, and other graphics. Download this action script: http://www.richinternet.de/blog/index.cfm?mode=month&month=11&year=2006 To use the SimpleGradientBorder class, you include the following in your style declaration: <mx:Style> .panel1filled { border-style: solid; border-thickness: 0; border-skin: ClassReference("border.SimpleGradientBorder"); fill-colors: #000099, #0099FF; corner-radius: 30; drop-shadow-enabled: false; color:#ffffff; font-size:12; font-weight:bold; } </mx:Style> The value for the border-skin attribute is the ActionScript class SimpleGradientBorder. You must also set the border-style to solid and provide two values for the fill-colors. The first value will be used at the top of the container and the second color value will be used at the bottom of the container and then the SimpleGradientBorder class will create a gradient fill between the two colors. Hope this helps.