minor error

i keep getting this error

Parse error: syntax error, unexpected $end in /public_html/test2.php on line 16

whats up with this code??

<?php
include "globals.php";
{
$price=($ir['hp']);
$chest=($ir['maxhp']);
$main=($chest - $price);
if($fm < $main)
echo "You can't afford to heal yourself";
else
$db->query("UPDATE users SET money=money-$main WHERE userid=$userid");
$query3="UPDATE users SET hp=hp+(maxhp/3) WHERE hp<maxhp";
$query4="UPDATE users SET hp=maxhp WHERE hp>maxhp";
$db->query($query3);
$db->query($query4);
print "You healed yourself";
?>

PHP:

dont worry about the variable $fm thats being called in from globals.php

 

You have an open brace '{' on line 2 but no closing brace. You probably also want to put braces '{}' around the lines after the else, otherwise it will just execute the first line as the else and the rest will always be executed.

 

Replace your code with

<?php
include "globals.php";

$main= $ir['maxhp'] - $ir['hp'];

if($fm < $main){
	echo "You can't afford to heal yourself";
} else {
	$db->query("UPDATE `users` SET money=money-".$main." WHERE userid=".$userid);
	$db->query("UPDATE `users` SET hp=hp+(maxhp/3) WHERE hp<maxhp");
	$db->query("UPDATE `users` SET hp=maxhp WHERE hp>maxhp");
	echo "You healed yourself";
}	
?>

Code (markup):

and it should work I assume $userid is also available from globals.php

 

@newgenservices hey buddy, thanks for your coding help, it really helped me loads !! cheers

 

You are welcome