Meaning of the code

if (!is_array($menu))
		return false;

PHP:

somebody pls explain the meaning of the above line of code . what it actually does?

 

If $menu is not in the array then do nothing.

 

looks like it should be in a function. Basically, ! means not. is_array returns true if the variable is an array of variables. So, basically if the variable is not an array then return false as the value and again it should be in a function so the var return for the function would be false if the gave var is not an array.

 

Hey,

exodus is right. It checks to see if the $menu variable is an array or not.

There are other similar functions, the best place to get answers from is http://uk.php.net/manual/en/function.is-array.php (and the rest of PHP.net) everything is documented.

Regards,

Steve

 

literally it checks if the variable $menu is not array, and returns false if it's true

 

Thanks to all those who gave solutions.. i understood the meaning..

thank you......