Math, who can prove it wrong?

Discussion in 'General Chat' started by comboy, Sep 21, 2007.

  1. JPRuss

    JPRuss Peon

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    #21
    null is the concept of "nothing", or the empty set. It is similar to zero but has some differences

    Lets say you have a bunch of oranges and a bunch of apples in a bucket, and I ask you to pull out of the bucket all things that are bannanas. What you would give me would be an empty set. If you were to count everything in that set you would get 0.

    null can also have specific meanings in programming, usually with regards to memory allocation and string manipulation
     
    JPRuss, Sep 21, 2007 IP
  2. Village_Idiot

    Village_Idiot Peon

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    #22
    Besides the fact the x is not a multiplier in algebra or above (this is flawed algebra), the problem does not add up.

    B = 2

    -a=b
    2 = 2 T

    -axa=axb
    2 . 2 = 2 . 2 T

    -axa-bxb=axb-bxb
    4-4= 4-4
    0 = 0 T

    -(a+b)x(a-b)=bx(a-b)
    4 . 0 = 4(0)
    0 = 0 T

    -(a+b)=b
    4 = 2 F

    a+a=a
    4 = 2 F

    2xa=a
    4 = 2 F

    2=1 !!! F

    The math has nothing do do with your problem, and some of it isnt even true.
     
    Village_Idiot, Sep 21, 2007 IP
  3. JPRuss

    JPRuss Peon

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    #23
    You mean that "x" is no longer an accepted algerbraic multiplication symbol?

    Hmm..it seems to be in a lot of elementry math books ;-)
     
    JPRuss, Sep 21, 2007 IP
  4. comboy

    comboy Well-Known Member

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    #24
    You can not prove an equation like this. It has to be in general.
     
    comboy, Sep 21, 2007 IP
  5. Village_Idiot

    Village_Idiot Peon

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    #25
    Its been a long time since highschool for me, but one of the things I do remember is that the got rid of the x because x is a variable. For example

    2x is 2 times x
    5(x+1) is five times (x plus one)

    They are next to each other if they are variables or numbers, if there are two numbers together they use a . like symbol.

    You will find X as a multiplier in any grade school math book however.



    I demonstrated how the equations math is flawed, it would not work with any number, the simple logic of it is not correct math. Unless its zero, a+a can not equal a.
     
    Village_Idiot, Sep 21, 2007 IP
  6. forumrating

    forumrating Notable Member

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    #26
    1st step is wrong

    a is not equal to b .
     
    forumrating, Sep 21, 2007 IP
  7. gr8liverpoolfan

    gr8liverpoolfan Notable Member

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    #27
    It isn't . He has assumed it to be , and is perfectly within his rights to do so. Although the moment he divides by zero, his whole puzzle goes for a toss.
     
    gr8liverpoolfan, Sep 22, 2007 IP
  8. comboy

    comboy Well-Known Member

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    #28
    It is not correct. Try again. First step is true.
     
    comboy, Sep 22, 2007 IP