logout not destroying variables

Discussion in 'PHP' started by mcf1992, Sep 22, 2011.

0
  1. #1
    Account.php

    <?php session_start(); ?><html xmlns="http://www.w3.org/1999/xhtml">  <head>  <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />  <LINK href="includes/css/style.css" rel="stylesheet" type="text/css"><title>Account Dashboard</title>  </head>  <body><?phpinclude('header.php');
include('dbsettings.php');
include('navbar	.php');

$con = mysql_connect("$host","$user","$password");  if (!$con)    {    die('Could not connect: ' . mysql_error());    }  
mysql_select_db("$db_name", $con);  $username= $_SESSION['username']; // Editted 
$sql="SELECT * FROM `user` WHERE `username`='{$username}'";  
$result = mysql_query("$sql");  ?><div class= "accountsummary"><?phpif($row = mysql_fetch_array($result)){
        $_SESSION['id'] = $row['id'];         $_SESSION['firstname'] = $row['firstname'];         $_SESSION['lastname'] = $row['lastname'];         $_SESSION['address'] = $row['address'];echo "ID:";       echo $_SESSION['id'];echo "<BR />";echo "First Name:"; echo $_SESSION['firstname'];echo "<BR />";echo "Last Name:"; echo $_SESSION['lastname'];echo "<BR />";echo "Address:"; echo $_SESSION['address'];

    } if($_SESSION['id']== ''){  echo '<META HTTP-EQUIV="Refresh" Content="0; URL=login.php">';    exit; }   
  ?>  </div>    <p class="logout">  <a href=logout.php>Logout</a>  </p>    <p style="position: absolute; top: 100px; left: 230px; background-color: white; margin: 15px; "> Welcome, <?php echo "$username"; ?> </p>  <?php
mysql_close($con); include('footer.php') ?>

</body>  </html>
    PHP:
    logout.php
    <?phpsession_start();
if(session_start())
{  session_destroy();}
header("location: login.php");?>
    PHP:
     
    mcf1992, Sep 22, 2011 IP
  2. jazzcho

    jazzcho Peon

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    #2
    jazzcho, Sep 22, 2011 IP
  3. mcf1992

    mcf1992 Peon

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    #3
    Already tried that did not work
     
    mcf1992, Sep 22, 2011 IP
  4. blueparukia

    blueparukia Well-Known Member

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    #4
    Unset each one individually:

    
<?php
    unset($_SESSION['id']);
    //etc.
?>
    PHP:
     
    blueparukia, Sep 22, 2011 IP
  5. mcf1992

    mcf1992 Peon

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    #5
    I tried that, yet no luck.
     
    mcf1992, Sep 22, 2011 IP
  6. fortehlolz

    fortehlolz Banned

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    #6 
    <?php
session_start();
unset($_SESSION['id']);

//or

$_SESSION['id']=false;
session_destroy();
unset($_SESSION['id']);
    PHP:
     
    fortehlolz, Sep 23, 2011 IP
  7. JohnnySchultz

    JohnnySchultz Peon

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    #7
    session_destroy(); is not really the answer in logging-out your user, maybe setting the $_SESSION to a blank array may be an answer..

    $_SESSION = array();
     
    JohnnySchultz, Sep 23, 2011 IP
  8. Vooler

    Vooler Well-Known Member

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    #8
    Even while using global $_SESSION array you first need to initialize sessions.

    <?php
session_start();
#here second call to session_start doesn't make sense and would probably issue warning and return false always
session_destroy();
header("location: login.php"); 

#if using php5 remove last ending tags to prevent any extra output after closing tags
?>
    PHP:
    or 


    <?php
session_start();

unset($_SESSION['id']); #this one was right too
header("location: login.php"); 

#if using php5 remove last ending tags to prevent any extra output after closing tags
?>
    PHP:
    Ty it and let me know.

    regards
     
    Vooler, Sep 23, 2011 IP
  9. NLZ13

    NLZ13 Well-Known Member

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    #9
    I always used this and it never failed me:
    <?php
session_start();
ob_start();
session_destroy();
header("location: main.php");
?>
    Code (markup):
     
    NLZ13, Sep 23, 2011 IP