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Login Page Usinhg PHP

Discussion in 'PHP' started by mandarj123, Mar 31, 2009.

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  1. #1
    I have been tryin to create simple login page using php witout success

    i juss want to give two fields userid and password nd if nyof they field is empty then on submit it shud throw an error sayin one or more fields are empty error shud be on same page on which textboxes r ther ther so error shud appear on top of entry boxes if validation fails and if its a success then it shud redirect to another page

    i have been very confused how to redirect and how to display error retaining textboxes on same page
     
    mandarj123, Mar 31, 2009 IP
  2. it career

    it career Notable Member

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    #2
    First post the code whatever you have got.
     
    it career, Mar 31, 2009 IP
  3. mandarj123

    mandarj123 Peon

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    #3
    <?php
    if (isset($_POST['Submit']))
    {
    if (!$_POST['UserId']||!$_POST['Password'])
    {
    die("Please Fill Required Details");

    }
    else
    header('Location:Logged.php');

    }
    else

    ?>
    <form action="<? echo $_SERVER['PHP_SELF']?>" method="post">
    UserName : <input type="text" name="UserId"> <br>
    Password: <input type="text" name="Password"><br>
    <input type="button" name="Submit" value="Submit">

    </form>

    Please Suggest Changes So tht I get Error On same Page If Fields Are Empty IF they Are Not Then on submit it shud redirect
     
    mandarj123, Mar 31, 2009 IP
  4. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #4
    Something like:
    
<?php
if (isset($_POST['Submit']))
{
if (empty($_POST['UserId'])) {
 $un_error = "<p class='error'>You didn't write a username</p>"; }
elseif ($_POST['UserId'] != <some check to see if user exist>) {
 $un_error = "<p class='error'>User do not exist</p>"; }
else {
$un_error = ""; }
if (empty($_POST['Password'])) {
 $up_error = "<p class='error'>Please fill in the password field</p>"; }
elseif ($_POST['Password'] != <password registered to UserId>) {
 $up_error = "<p class='error'>Wrong password - please try again</p>";  }
else {
$up_error = ""; }
if (isset($_POST['UserId']) == <user ID from db or something>) && (isset($_POST['Password']) == <userIDs password>) && $un_error == "" && up_error == "") {
header('Location:Logged.php'); }
else {
?>
<form action="<? echo $_SERVER['PHP_SELF']?>" method="post">
<p>UserName : <input type="text" name="UserId" /></p>
<?php echo $un_error; ?>
<p>Password: <input type="text" name="Password" /></p>
<?php echo $up_error; ?>
<p><input type="button" name="Submit" value="Submit" /></p>
</form>
    PHP:
    This isn't a complete code-example - there should be some more error-checking added and such, before submitting to the logged-in page, but you should get the general idea
     
    PoPSiCLe, Mar 31, 2009 IP
  5. mandarj123

    mandarj123 Peon

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    #5
    how does above code differ from what i have wrote except i dont want to check if user exists :(
     
    mandarj123, Mar 31, 2009 IP
  6. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #6
    Try the latest code - you can remove the checks for user/password if you want, but the page is more or less useless without some verification of the user somehow.

    Anyway - as the code is now, it should provide the form again, showing the errors unless the $un_error and $up_error blocks does not show anything - if they are empty, user will be redirected to the logged-in page, if there are errors on the page, the form will be shown.
     
    PoPSiCLe, Mar 31, 2009 IP
  7. mandarj123

    mandarj123 Peon

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    #7
    <?php
    if (isset($_POST['Submit']))
    {
    if (!$_POST['UserId']||!$_POST['Password'])
    {
    echo("Please Fill Required Details");

    }
    else
    header('Location:Logged.php');

    }
    else
    ?>
    <form action="<? echo $_SERVER['PHP_SELF']?>" method="post">
    UserName : <input type="text" name="UserId"> <br>
    Password: <input type="text" name="Password"><br>
    <input type="button" name="Submit" value="Submit">
    </form>

    the code doesnt work first time it shows proper screen but nothing happens wen i click on sibmit button
     
    mandarj123, Mar 31, 2009 IP
  8. OinkOink

    OinkOink Peon

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    #8
    Try this:

    
<?php
if (isset($_POST['submit']))
{
	if (!$_POST['UserId']||!$_POST['Password'])
	{
		echo("Please Fill Required Details");
	}
	else
	{
		header('Location:Logged.php');
	}
}
?>
<html>
	<body>
		<form action="<?php echo $_SERVER['PHP_SELF']?>" method="post" accept-charset="utf-8">
		UserName : <input type="text" name="UserId"> <br>
		Password: <input type="text" name="Password"><br>
		<input type="submit" name="submit" value="Submit">
		</form>	
	</body>
</html>
    PHP:
     
    OinkOink, Mar 31, 2009 IP
  9. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #9
    First, check to see if the PHP_SELF variable actually produces the desired result - ie. shows a link to the file.

    Then, change the <input type="button" to <input type="submit" and try again
     
    PoPSiCLe, Mar 31, 2009 IP
  10. adstiger

    adstiger Peon

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    #10
    I don't think that changing the input type will help in this case.
     
    adstiger, Mar 31, 2009 IP
  11. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #11
    Nope, it won't, but that doesn't mean it shouldn't be fixed :)

    The following code is tested, and it works:
    
<?php
$username = "testuser";
$password = "password";

if (isset($_POST['submit']))
{
	if (empty($_POST["userid"])) {
		$un_error = "<p class='error'>You didn't write a username</p>";
	}
		elseif ($_POST["userid"] != $username) {
	 		$un_error = "<p class='error'>User do not exist</p>";
	 	}
	else { $un_error = ""; }
	if (empty($_POST["password"])) {
		$up_error = "<p class='error'>Please fill in the password field</p>";
	}
		elseif ($_POST["password"] != $password) {
			$up_error = "<p class='error'>Wrong password - please try again</p>";
		}
	else { $up_error = ""; }
} if ((isset($_POST["userid"])) && (isset($_POST["password"])) && $un_error == "" && $up_error == "") {
		echo "It worked"; }
	//header('Location:Logged.php'); }
		else {
			?>
			<form method="post" action="http://www.regncon.no/testpage.php">
			<p>UserName : <input type="text" name="userid" value="<?php echo $_POST['userid']; ?>"/></p>
			<?php echo $un_error; ?>
			<p>Password: <input type="password" name="password" /></p>
			<?php echo $up_error; ?>
			<p><input type="submit" name="submit" value="Log-in" /></p>
			</form>
		<?php } ?>
    PHP:
    As you can see, I've substituted the header() after success with a simple echo-statement, as I didn't care for making both files - just remove the line with the echo-statement above, and uncomment the header-line to get it to work for you.

    The variables at the start of the script is just to match the error-checking against something.
     
    PoPSiCLe, Mar 31, 2009 IP
  12. mandarj123

    mandarj123 Peon

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    #12
    above code works but if i replace
    echo "It worked";

    above line with this one

    header('Location:Logged.php');

    then i am getting error

    Warning: Cannot modify header information - headers already sent by (output started at D:\PhpDevelopment\Login.php:1) in D:\PhpDevelopment\Login.php on line 20

    thanx in advance:(
     
    mandarj123, Mar 31, 2009 IP
  13. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #13
    Read up on buffering, here:
    http://www.phpbuilder.com/board/showthread.php?s=&postid=10453971

    It's basically that you are trying to send headers out after pushing content to your page - use ob_start() and ob_end_flush() to put output buffering on and off. Or change the php.ini to always allow output buffering. PS! Might have security risks!
     
    PoPSiCLe, Mar 31, 2009 IP
  14. adstiger

    adstiger Peon

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    #14
    Output buffering always have risk. It wil make the application unsecured.
     
    adstiger, Mar 31, 2009 IP
  15. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #15
    It is already insecure, as it is, so putting in output buffering won't hurt... if one encrypts the POST-variables, it won't matter all that much either.
     
    PoPSiCLe, Mar 31, 2009 IP
  16. mandarj123

    mandarj123 Peon

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    #16
    can you temme where and how exactly to use ob_start and ob_flush concept
    i hav juss started learning php so im not worrying abt security aspect i just want to make things work step by step

    thanx for help:)
     
    mandarj123, Apr 1, 2009 IP
  17. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #17
    Insert the ob_start(); function as the first line in the php-code - ie:
    
<?php
ob_start();
$username = "testuser";
$password = "password";
    PHP:
    Insert the ob_end_flush(); before the last ?>
     
    PoPSiCLe, Apr 1, 2009 IP
  18. mandarj123

    mandarj123 Peon

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    #18
    i tried it but it doesnt work same error

    Warning: Cannot modify header information - headers already sent by (output started at D:\PhpDevelopment\Login.php:1) in D:\PhpDevelopment\Login.php on line 24
     
    mandarj123, Apr 1, 2009 IP
  19. PoPSiCLe

    PoPSiCLe Illustrious Member

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    #19
    Hmm... it should work. Can you just post your complete code here? Just mark all, and copy the exact code in between PHP-tags. You might have some spaces or something that is being sent before the header/ob_start()
     
    PoPSiCLe, Apr 1, 2009 IP
  20. mandarj123

    mandarj123 Peon

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    #20
    <?php

    ob_start();
    $username = "testuser";
    $password = "password";
    if (isset($_POST['submit']))
    { if (empty($_POST["userid"]))
    { $un_error = "<p class='error'>You didn't write a username</p>";
    } elseif ($_POST["userid"] != $username)
    { $un_error = "<p class='error'>User do not exist</p>";
    } else
    { $un_error = "";
    }
    if (empty($_POST["password"]))
    { $up_error = "<p class='error'>Please fill in the password field</p>";
    } elseif ($_POST["password"] != $password)
    { $up_error = "<p class='error'>Wrong password - please try again</p>";
    } else { $up_error = ""; }
    }
    if ((isset($_POST["userid"])) && (isset($_POST["password"])) && $un_error == "" && $up_error == "")
    { // echo "It worked";


    header('Location:Logged.php');

    }

    else
    {
    ?>
    <form action="<?php echo $_SERVER['PHP_SELF']?>" method="post"
    <p>UserName : <input type="text" name="userid" value="<?php echo $_POST['userid']; ?>"/></p>
    <?php echo $un_error; ?>
    <p>Password: <input type="password" name="password" /></p>
    <?php echo $up_error; ?>
    <p><input type="submit" name="submit" value="Log-in" /></p>
    </form>
    <?php
    }
    ob_flush();
    ?>
     
    mandarj123, Apr 2, 2009 IP
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