Hi, can anyone explain why this does not work? I have the following on page: <div id="bob">hello</div> Now in my javascript file i have this: var i = "bob" var tmp = document.getElementById(i) $(tmp).remove(); Ok? the above seems to work fine. When i remake the div with the same id: "bob" again, it is a new div. BUT when i try this: var i = "bob" var tmp = document.getElementById(i) $(tmp).slideUp("slow")(function (){ $(tmp).remove(); } ) It slides up, and appears to remove, but when the div is remade with the same id: "bob", the old one appears to come back, with all the old data in it. Can anyone help? Many thanks!!!
You're not setting the callback function properly in your slideUp function. You don't close the parenthesis then open a new one, you simply put a comma. var i = "bob" var tmp = document.getElementById(i) $(tmp).slideUp("slow", function (){ $(tmp).remove(); }); By the way, you're already using the awesome power of jQuery, why would you use document.getElementById?! Just do $("#bob")
Thanks zerxer! I havent tried your code yet, but it makes sense. So would i do this? $("#" + var) e.g: $("#" + i) Also, is there anyway to replace this: for(i=0;i<10;i++){ } with a jquery function? I'm just getting started, im so used to writing my own javascript, its hard to get going with jquery Thanks for the help
Yeah, $("#" + i) would work fine. If you want to reference by class name, you'd use a period instead of pound (#) symbol. Eh, there is a looping function in jQuery, but it's for looping through objects/json object. $.each(something, function(){//do something with 'this'}); where var something = $("div") (to fetch all divs) or where var something = {name1: 'value', name2: 'value'}; (your own JSON object). The documentation on jQuery's site is very useful for easily learning all the functions they offer. Also, if you ever need help again with jQuery, I recommend trying out their IRC chat (if you have an IRC client) as it always has people in it with a few that are active at any given time and they can help you. I sometimes join that chat to try to answer people's questions.