is it this type of post possible?

hi is it possible to post a variable like this either with javascript or php i tried here with javascript but didnt work is there a similiar way of doing with php??

query.php

<?php
include("../../includes/config.php");
mysql_connect($db_address, $db_username, $db_password);mysql_select_db($db_name) or die(mysql_error());
$fid = $_GET['fid'];	
$fid = mysql_real_escape_string($fid);
$query10 = "SELECT * FROM films WHERE (film_id = '$fid')";	
$qry_result10 = mysql_query($query10) or die(mysql_error());
while($row10 = mysql_fetch_array($qry_result10))	
{	$urlfid="http://www.onfilm.biz/streaming/home/".$row10['client']."/".$row10['client_office']."/".$row10['filename'].".mp4";?>		
<a class="hofwhite14" href="#" onclick="loadNplay('<?php echo $urlfid; ?>')"><u></u>Property Film</u></a>
<?php	}mysql_close();
 //EDIT 290510
?>

<script type="text/javascript">

var video= $urlfid;
$.post('indextest.php', {urlfid:video});

</script>

Code (markup):

 

<script type="text/javascript">

var video= <?php echo $urlfid; ?>;
$.post('indextest.php', {urlfid:video});

</script>

HTML:

Is it what you're looking for?

 

yes i think so but
so if i have that will post post that variable into the indextest.php
<script type="text/javascript">
var video= <?php echo $urlfid; ?>;
$.post('indextest.php', {urlfid:video});
</script>
so the overall code would be
film.php

<?php
include("../../includes/config.php");
mysql_connect($db_address, $db_username, $db_password);mysql_select_db($db_name) or die(mysql_error());
$fid = $_GET['fid'];	
$fid = mysql_real_escape_string($fid);
$query10 = "SELECT * FROM films WHERE (film_id = '$fid')";	
$qry_result10 = mysql_query($query10) or die(mysql_error());
while($row10 = mysql_fetch_array($qry_result10))	
{	$urlfid="http://www.onfilm.biz/streaming/home/".$row10['film_client']."/".$row10['film_client_office']."/".$row10['film_filename'].".mp4";?>		
<a class="hofwhite14" href="#" onclick="loadNplay('<?php echo $urlfid; ?>')"><u></u>Property Film</u></a>
<?php	}mysql_close();
 //EDIT 290510
?>


<script type="text/javascript">

var video= <?php echo $urlfid; ?>;
$.post('indextest.php', {urlfid:video});

</script>

PHP:

and indextest.php

<?php $urlfid = $_GET['urlfid']; 

echo $urlfid; ?>

PHP:

is that right if so is not working

 

In indextest.php you get urlfid variable in $_POST table, so:

<?php $urlfid = $_POST['urlfid']; 

echo $urlfid; ?>

PHP:

 

so wher ethis POST line meant to be on the indextest.php or on the film.php film page is where the database query is and the indextest.php is where i am trying to display the query?

 

You're sending a POST data to indextest.php so you need to put it there if you want to do so.

 

yeah but the data is coming from fillm.php are you sure you dont mean to put this script

<script type="text/javascript">
var video= <?php echo $urlfid; ?>;
$.post('../bellway/indextest.php', {urlfid:video});
</script>

PHP:

on the film.php where the data is
and how does the indextest.php grabs or echo the data that came from the film.php
and do i need a from with that cz i am trying to do without using from?

 

From i meant FORM

 

indextest.php has that variable in $_POST table beacuse it's sent by AJAX function from film.php in line:

$.post('indextest.php', {urlfid:video});

HTML:

 

Hi thanks for the help but maybe is me trying the hard way perhaps you can help me the reason i am trying to do this is to try achieve something i have posted on another thread can you help me out please this the thread
http://forums.digitalpoint.com/showthread.php?t=2272591