Image Format Detection

Im trying to detect the format of an image. But I get a parse error

<?php
$filename = 'http://static.php.net/www.php.net/images/php.gif';
$file = fopen($filename, 'rb');
$size = getimagesize($file);
        switch ($size['mime']) {
    case "IMAGETYPE_GIF":
        echo "Image is a gif";
        break;
    case "IMAGETYPE_JPEG":
        echo "Image is a jpeg";
        break;
    case "IMAGETYPE_PNG":
        echo "Image is a png";
        break;
?>

PHP:

 

You didn't close the { that you opened on the switch() line.

 

yeah I just realised lol