If database field = Y display image

Hey,

I am created a php page where I print info from a database using

<td><?=$mf['receivep']?></td>

I would like it that if receivep = y it will show a tick if it = n it will display a image of a x.

How do I do that.

Rgds
Daniel

 

<td><?
if ($mf['receivep'] == "n")
{
   echo '<img src="image_x.png">';
} else {
   echo '<img src="image_y.png">';
}
?></td>

PHP:

In this case the it will show the image_x.png if it is "n" otherwise it will show the image_y.png

 

Hey guy,Try this:
<td>
<?php
if($mf['receivep'] == 'y')
{
?>
<img src="The image url what you want to show.">
<?php }else{ ?>
<img src="The image url what you want to show.">
<?php } ?>
</td>

 

Thanks works like a charm!