I need help with splitting a string

I have a script that I want to modify by taking the first letter out of it, adding a figure to the remainder and then adding the first letter back in.

This probably sounds like double dutch so here it is in more understandable english:

I want to remove the first character out of this string $string . This string varies in value but the first character is always £ .
I want to remove the £ and leave the remaining value e.g. 20.00 or 1000.00.

I then want to add a figure to it.
e.g. say 10.00 add 1.50 to equal 11.50

I then want to add the £ back in to finish up with £11.50

Any help would be appreciated.

John C

 

Try something like this...

$string = '$20.00';

$chop = intval(substr($string, 1)); // $chop now is 20.00
$add = 10;

$total = $chop + $add; // total now is 30

$finalValue = '$' .$total; // should be $30.00

 

you should use floatval() not intval()

 

Hi Guys...
Many thanks for your help.
However, I have played about with this code, using both floatval() and intval(), but the final result drops the final 0's
I have also tried strval() with the same results.
i.e.
If the final value of $chop + $add; is £30.00 it is displayed as £30 (without the final 2 00's)
If the final value of $chop + $add; is £30.50 it is displayed as £30.5 (without the final 0)
If the final value of $chop + $add; is £30.95 it is displayed as £30.95 (which is what I want)

This project is to add into a shopping cart that has no facility for adding carriage to the final total so it is important that I get the final result to 2 decimal places.

Any other thoughts will be appreciated.

Regards,

John C

 

string money_format ( string $format , float $number )

http://php.net/manual/en/function.money-format.php

with this function you can specify the number of decimal places to display along with other stuff

 

Hi shofstetter..

Thanks for your help.
I couldn't get money_format() to work as I needed it.
However, whilst trying I came across number_format() which worked a trreat for me.

Thanks for your help.

John C

 

I tried that. It works for sure. Thanks all for the good tip.

 

You can also do:

$amount = '£20.00';

echo str_replace('£', '', $amount);

// or

echo str_replace('£', '', $amount);   // if reading string from a url

PHP: