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How would i do this ....

Discussion in 'Databases' started by laserfink, Sep 17, 2013.

0
  1. #1
    trying to do a mate a favour ... but kinda stuck , seems simple enough idea , maybe mysql is overkill , maybe php or java better , im really going to need spoonfed PLEASE !

    Need on screen 1500 boxes , numbered 1-1500 , so thats ten boxes across x 150 lines of boxes down , boxes maybe 2cm square ?

    at top there needs to be totals

    Each box should contain a number and be CLickABLE to scroll through six options , as you scroll through the options , the totals at top change

    Once correct option chosen , a checkbox within the box can be clicked to STICK the box so it cant be changed

    sound easy ? how do i move forward
     
    laserfink, Sep 17, 2013 IP
  2. bartolay13

    bartolay13 Active Member

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    #2
    really lost with your instruction, is this some like you need result set from database and just displaying it on table inside a website?
     
    bartolay13, Sep 17, 2013 IP
  3. laserfink

    laserfink Active Member

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    #3
    Thanks for getting back to me , your right , i think i may be over complicating this

    This could easily be done in excel , but how do i get this displayed on website ?
     
    laserfink, Sep 18, 2013 IP
  4. sarahk

    sarahk iTamer Staff

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    #4
    Building the boxes is easy enough, the animation can be done with HTML5 pretty easily and the checkbox to lock the box can be written in javascript.

    If the values need to be saved that's easy too - either through ajax or submitting the page.
    <div class='gridrow'>
<div class='totalcell' id='totalcolumn1'>
<div class='totalcell' id='totalcolumn2'>
<div class='totalcell' id='totalcolumn3'>
<div class='totalcell' id='totalcolumn4'>
<div class='totalcell' id='totalcolumn5'>
</div>
<?php for($i = 0; $i < 1500; $i++) {
if ($i%5 == 0) echo "<div class='gridrow'>";
?>
<div class='unitcell' id='unit<?php echo $i; ?>'>
<!-- input values go here -->
<input name='something<?php echo $i; ?>' id='something<?php echo $i; ?>' value=''>
</div>
<?php
if ($i%5 == 4) echo "</div>";
}?>
    PHP:
    the key is in putting the right css against it - and you'll need a designer to help you with that, I reckon
    add jquery listeners onto the page to see when the values of the input values change
     
    sarahk, Sep 19, 2013 IP