How to use php upload file from host to another host?

- Description: i have a file test.zip at here: http://host_1.com/test.zip
- I have a php host at here: http://host_2.com
- And i need a php code put in host_2.com to upload file test.zip to http://host_3.com/upload_process.php
- upload_process.php is php file, it process file upload (HTTP POST)

- With some knowledge about php, i think use fsockopen, read file test.zip at http://host_1.com/test.zip, send some header, and send it to http://host_3.com/upload_process.php as same as when use html form post to upload file normally

- But i don't know in detail how to do it?
- Can anyone help me?
- Thanks.

 

You can use cURL.

http://www.php.net/curl

If both hosts are yours, I'd recommend using FTP though.

http://www.php.net/ftp

 

- Target host is not mine
- And can you give me some detail or example to do it with curl?

 

Just follow the links nico provided and you'll get the help you need. You should use FTP to do this.

 

@nico_swd, klown: Thanks, i founded it, thanks.

 

- I found a way to upload file, but it only do well with local file:

$post_data = array();
  
//$post_data['file'] = "http://mirror2.internetdownloadmanager.com/idman509.exe";

$post_data['file'] = "@test.zip";
  
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, "http://host.com/upload_process.php" );
curl_setopt($ch, CURLOPT_POST, 1 );
curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$postResult = curl_exec($ch);

if (curl_errno($ch)) {
 print curl_error($ch);
}
curl_close($ch);
print "$postResult";

Code (markup):

- I have a idea is transfer file need upload to host and upload load it as local file, but seem it waste a lot of bw.

- any suggestion? Thanks

 

use ftp......

 

{@:

- Target host is not mine, i don't have ftp account >.<

}

 

You can do:
1. Create a finction like this:

function url_copy($source)
{
	$d=explode("/",$source);
	$dest=$d[count($d)-1];
	$f1=fopen($source,"rb");
	$f2=fopen($dest,"w");
	echo "<SCRIPT>window.status='Copying \'$source\' to \'$dest\'...';</SCRIPT>\n";
	flush();
	while ($buff=fread($f1,1024))
	fwrite($f2,$buff);
	fclose($f1);
	fclose($f2);
	$size=filesize($dest);
	echo "<SCRIPT>window.status='$size bytes copied.';</SCRIPT>\n";
}

PHP:

2. And do as you wish!