how to use GETIMAGESIZE() function

<?php
$size = getimagesize($filename);
$fp = fopen($filename, "rb");
if ($size && $fp) {
    header("Content-type: {$size['mime']}");
    fpassthru($fp);
    exit;
} else {
    // error
}
?>

PHP:

I have replaced $filename with 'watermark.png'

The result is http://crazyjunction.com/GD/1.php

 

getimagesize() use to get the information of an image, this is example:

your code is ok but http://crazyjunction.com/GD/1.php code error because you echo somethings above the header() function line

 

you can use imagick.
see the sample here: http://hk2.php.net/manual/en/function.imagick-getimagesize.php
it really simple.

 

never put echo about header()