hello all, I am trying to lerarn how to update database. Everything is fine but after the update is done it is still showing the content which was before the update. if i put the browser off and on again there is no problem, it is showing the updated content. What can i do to show the updated content after pressing submit? Thanks <?php $host="localhost"; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name="test"; // Database name $tbl_name="test_mysql"; // Table name mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); $count=mysql_num_rows($result); ?> <table width="500" border="0" cellspacing="1" cellpadding="0"> <form name="form1" method="post" action=""> <tr> <td> <table width="500" border="0" cellspacing="1" cellpadding="0"> <tr> <td align="center"><strong>Id</strong></td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Lastname</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td> <td align="center"><input name="name[]" type="text" id="name" value="<? echo $rows['name']; ?>"></td> <td align="center"><input name="lastname[]" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td> </tr> <?php } ?> <tr> <td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td> </tr> </table> </td> </tr> </form> </table> <?php // Check if button name "Submit" is active, do this if($Submit){ for($i=0;$i<$count;$i++){ $sql1="UPDATE $tbl_name SET name='$name[$i]', lastname='$lastname[$i]' WHERE id='$id[$i]'"; $result1=mysql_query($sql1); } } if($result1){ echo "<h4>Updated</h4>"; } mysql_close(); ?> PHP:
ok... sorted. i changed echo "<h4>Updated</h4>"; PHP: with echo "<meta http-equiv=\"refresh\" content=\"0;URL=index.php\">"; PHP: