How to SEND dropdown list value to FORM with method POST?

<?php $query= "SELECT date, id FROM Puspa ORDER BY id ASC";
$result = $db_connect->query($query);
?>
<form action="output.php" method="post">
<select name='p'>
<?php
while (list($date, $id) = $result->fetch_row()) {
echo "<option value=\"$id\"> $id : $date</option>";
}

?>
</select>
<input type="submit" value="submit"/><br />
</form>

I've dynamically listed my result in dropdown list as the code above.

I would like to know the shortcut and secure way to submit the SELECTED value using POST method.

How to do this?

 

just pull the data after submission as

if($_POST['p']){
$item = $_POST['p'];
}

Then you can sanitize it after you grab the submitted data.

 

Are you sure about it?
The HTML code for drop down list will look like this:

<select name='p'>
<option value='1'>Value 1</option>
<option value='2'>Value 2</option>
<option value='3'>Value 3</option>
</select>

how will it pull the value? I know how to pull the value. But I wanted to get for example, Value 2 in $_POST['p']....

 

lowridertj is correct. The post value "p" is populated with what is selected in the dropdown.

Also, don't forget to use "==" in your while loop:

while (list($date, $id) == $result->fetch_row())

HTML:

 

Can i know what's that == is for? I don't think it's right place to use ==!

 

@lowridertj thanx it worked.

 

no problem glad it worked out for you.

 

http://php.net/manual/en/language.operators.comparison.php