How to retrieve a patterned string from a paragraph

hi gurus,

i have a string

how can i retrieve the text
http://img215.imageshack.us/img215/1886/cleard.jpg

Thanks for the guide

 

Your code would be something like this:

<?php
$regex = ''; // REGEX HERE
$string = 'some text...
[img:304uninl]http://img215.imageshack.us/img215/1886/cleard.jpg[/img:304uninl]
some text... ';

preg_match($regex, $string, $matches);

print_r($matches);

PHP:

Unfortunately, I do not understand regular expressions so someone will need to pick up where i left off.

 

$regex = '%\](^\[)+\[';

I am not sure BTW.

 

Hah, you got farther than I did. This is what it came up with:

 

oh sorry it is...

$regex = '%\](^\[)+\[%';

 

i have run my code

<?php

$regex = '%\](^\[)+\[%'; // REGEX HERE
$string = 'some text...
[img:304uninl]http://img215.imageshack.us/img215/1886/cleard.jpg[/img:304uninl]
some text... ';

preg_match($regex, $string, $matches);

print_r($matches);
?>

PHP:

return NULL

 

<?php

$string = <<<STRING
some text...
[img:304uninl]http://img215.imageshack.us/img215/1886/cleard.jpg[/img:304uninl]
some text... 
STRING;

$text = explode("\n", $string);

//the first text
print($text[0]); 

//the second lot of text
print($text[2]);

?>

PHP:

 

You should use the 's' modifier, since the text being match'd contains new lines.

 

$str = "[img:304uninl]http://img215.imageshack.us/img215/1886/cleard.jpg[/img:304uninl]";
$exp =  explde("uninl]",$str); // explode the start point
$pos = strpos($exp[1],"[/"); // position the end point
$sub = substr($exp[1],0,$pos); // cut the link
echo $sub;

PHP:

If there are more links on page then

$str = "[img:304uninl]http://img215.imageshack.us/img215/1886/cleard.jpg[/img:304uninl]";
foreach(range(1,20) as $range) { // from,to array values
$exp =  explde("uninl]",$str); // explode the start points
$pos = strpos($exp[$range],"[/"); // get position of end points
$sub = substr($exp[$range],0,$pos); // cut the link
echo $sub; echo "<br>"; }

PHP: