How to replace a $variable with a $variable and parse?

Discussion in 'PHP' started by 123GoToAndPlay, Mar 29, 2011.

  1. #1
    Hello,

    I am looking for a way to get my layout in a variable and use it in a foreach, see

    
    function showDivs($array) {
    
    $luxury = array();
    $not_luxury = array();
    foreach ($array as $value) {
        if ($value["MinimumRate"] > 500) {
            $luxury[] = $value;
        } else {
            $not_luxury[] = $value;
        }
    }$layout = $value['Description'] . " : " . $value["MinimumRate"] . "<br />";
    
    $return = '<div id="no_luxury" >';
    
    foreach ($no_luxury as $value) {
        $return .= $layout;
    }
    
    $return .= '</div>';
    
    $return .= '<div id="luxury" >';
    
    foreach ($luxury as $value) {
        $return .= $layout;
    }
    
    $return .= '</div>';
    
    return $return;
    
    }
    
    Code (markup):
    Any tips?
     
    123GoToAndPlay, Mar 29, 2011 IP
  2. s_ruben

    s_ruben Active Member

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    #2
    Can you explain more about your problem?
     
    s_ruben, Mar 30, 2011 IP