how to print only repeated number.....

I want to display number which are repeated.

$arr = array('1', '2', '1', '3', '4', '2', '7', '5', '6', '7', '1', '8', '9');
here 1, 2, 7 are repeated and i want to echo only these 3 element which are repeated.
result like this :
1
2
7
without any php function using only loop(for, foreach, while, etc.)
plz help..................
thanks...................

 

Try this:

$arr = array('1', '2', '1', '3', '4', '2', '7', '5', '6', '7', '1', '8', '9');
$result=array_unique(array_diff_assoc($arr,array_unique($arr)));
foreach($result as $result1) {
    echo $result1, '<br>';
}

PHP:

 

thanks for reply..................
but my condition is that you can't use these function
array_unique_and_array_diff_assoc
without using these function only use loop or some thing other...........
thanks..........

 

Why can't you use that function?
You can't do it without using some sort of PHP functions.

 

You can use the basic code as below

<?php
$arr = array('1', '2', '1', '3', '4', '2', '7', '5', '6', '7', '1', '8', '9');
$tempArr = array();
foreach($arr as $eachElement)
{
if(!in_array($eachElement, $tempArr))
{
echo $eachElement."<br/>";
$tempArr[] = $eachElement;
}
}
?>

 

^ The above will print 1271, and it uses in_array

Here is my solution:

$arr = array('1', '2', '1', '3', '4', '2', '7', '5', '6', '7', '1', '8', '9');
$tempArr = array();
$uniques = array();


foreach($arr as $eachElement){
    if (in_php_arr($eachElement, $tempArr) && !in_php_arr($eachElement, $uniques)){
       $uniques[] = $eachElement ;
    }
    else {
        $tempArr[] = $eachElement ;
    }
}

foreach ($uniques as $e) {
    echo $e ;
}


function in_php_arr($val , $tempArr){
    foreach ($tempArr as $temp) {
        if ($temp ==$val ){
            return true ;
        }
    }
    return false ;

}

PHP:

Although I am sure there is a simpler solution somewhere..

 

thanks for help

 

thanks for help..........