How to prevent a function executes after being executed

Hi,
Is there anyway to stop function c executes again after it is being executed by function a.

var a = function() {
   c(1);
}
var b = function() {
   c(2);
}
var c = function(i) {
   var d = 3 + i;
   console.log(d);
}
a();
b();

Code (markup):

Thank you,

 

Javascript supports function overloading; more so since you made it a classed variable.

So undefine it in 'a'.

c = null;

 

Well I'm not necessarily sure it's a great idea to completely overwrite c. He merely wants to prevent it from executing in b is what I'm gathering.

A basic example using the existing code would be to set a Boolean variable specifying whether or not c can be executed.

var executeC = true;
var a = function() {
   c(1);
   executeC = false;
}
var b = function() {
   if (executeC) {
      c(2);
   }
}
var c = function(i) {
   var d = 3 + i;
   console.log(d);
}
a();
b();

Code (markup):

 

Instead of setting it to null, I would set it to a null function. That way it wouldn't error if it is called again:

var a = function() {
   c(1);
   c = function () {};
}

Code (markup):

 

Your best bet is to do it this way :-

var a = function (){
    c(1,true);
}
var b = function (){
    c(2,false);//or simply c(2);
}
var c = function (i,execute){
    if(!execute)return;
    var d = 3 + i;
    console.log(d);
}
a();
b();

Code (markup):

 

Spaceman12 your code is wrong. In your example if you only call b(); without a(); beforehand the code in C will never execute even though it is intended to do so.

I like Iconiplex implementation the best.