How to pregmatch word in string

Hey, How I can pregmatch domain base in this example
"http://www.caasco.com/automotive/";


I need to extract caasco.com in this example

 

http://www.php.net/parse_url

 

Hello,
I don't know for sure if this will work with php. Here is regex string in c#:

(?:"http://www.)(?.*)(?:.com/automotive/")

Hope it helps. Do a few tests until you get it right.
The idea is that ?: will make it so the text won't be added in the final mat ch.

 

parse_url() and str_replace('www.', '', $parse['host']) is much faster than using preg_match.

But there is no solution working with all tlds without using a complexe whitelist. f.e. you aren't able to find the domain:

For the most of all cases, I'm using this:

function getdomain($url) {
	// add scheme
	if (strpos($url, '://') === false) {
		$url = 'http://' . $url;
	}
	// filter host
	$p = parse_url($url);
	$host = $p['host'];
	if ($host{0} . $host{1} . $host{2} . $host{3} == 'www.') {
		$host = substr($host, 4);
	}
	// filter domain
	$p = explode('.', $host);
	$cp = count($p);
	return ($p[$cp-1] == 'uk' || $p[$cp-2] == 'com' || $p[$cp-2] == 'co' || $p[$cp-1] == 'pro') ? ($p[$cp-3] . '.' . $p[$cp-2] . '.' . $p[$cp-1]) : ($p[$cp-2] . '.' . $p[$cp-1]);
}

Code (markup):

If you only want the domain of your host, you should go better with that:

$domain = strtolower(str_replace(array('www.', 'ww.', ':80'), '', $_SERVER['SERVER_NAME']));
$domain = $domain{strlen($domain)-1} != '.' ? $domain : substr($domain, 0, -1);

Code (markup):

 

Thank you very much for all your help, but I still need your help.

Like I am creating script which counting number of external links on the page,
1) I am parsing page
2) Getting all links on page
3) the problem I hit is I can not figure out how to find the difference between urls like:
bigger.html
bigger.com

first I were thinking to pregmatch to domain extension like ".com", but then I realize that so many domains extension that its too crazy,
what you can suggest ?