How to parse a variable before the include

Hi, I am using dirname($_SERVER['SCRIPT_FILENAME']); and including the file in other files. the way it is now, it gets the directory of the file that is calling the include. I want it to use the directory of the file that is being included.
How do I do this?
Thanks

 

It looks like you want the PHP __FILE__ "magic" constant.
dirname(__FILE__) should then give you the directory of the file that has been included.

More information on __FILE__ and other "magic" constants:
http://www.php.net/manual/en/language.constants.predefined.php

 

No, I don't want to use __FILE__

 

It would seem to work in the situation you described, and provide you with the desired results.
Is there any specific reason you'd prefer not to use the __FILE__ constant?

 

I changed from $_SERVER[SCRIPT_FILENAME] to http:// . $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI']}
So __FILE__ Does not achieve the correct results.