How to > if values in array exist in the sentence ?

Hello,

I want to do something if my sentence include one of the words in this array, How to do that ?

$sentence = "I dont give a shit";

$values = array("lick","shit","pussy","horny");

PHP:

Thanks...

 

$sentence = "I dont give a shit";

$values = array("lick","shit","pussy","horny");
$found = 0;
foreach($values as $val) {
 if(strpos($sentence,$val) != -1) {
  //found one
  $found = 1;
 }
}
// if it found one or more $found = 1 else $found = 0

PHP:

this is just one way.. there are more ways to do this..

 

Personally I'd use a boundary based regex of the words

function to_regex($string) {
    return '%\b'.preg_quote($string).'\b%i';
}
$filter = array_map('to_regex', $values);
foreach($filter as $val) {
    if(preg_match($val, $sentence) {
        //Do whatever here
    }
}

PHP:

EDIT: Also, this is case insensitive

Also, use google for this kind of thing, they're out there in the thousands
http://www.google.com/search?hl=en&q=php+word+filter&aq=f&oq=&aqi=g1