How to get the date of 3 days later of today

I know date("Y/m/d") is to get today's date like 2008/09/26, and now I want to know the date of 3 days later from date("Y/m/d"). How to do that?

How to automatically increase date? For example, after getting date("Y/m/d"), now I want to show the date after it one by one.

 

$three_days_later = strtotime("+3 days"); //in timestamp

// get it in date form
$newdate = date("Y/m/d",$three_days_later);

//print it out 
print $newdate;

PHP:

 

Think i'd make use of the mktime() function

$threeDaysLater = date("Y/m/d", mktime(0, 0, 0, date("m") , date("d")+3, date("Y")));

 

mktime and strtotime can achieve want you want done

 

How to increase the date by one day continuously?

 

in what way? perhaps use a loop.

$num_loop = 40; // number of loops :: start from today, print 40 dates
for ($looped=0;$looped<$num_loop;$looped++) {
print date("Y/m/d" , strtotime("+$looped days") ); // print out the date
}

PHP:

or you want to assign them to an array?

 

Yes, I want to assign it to an array.

Another question, if I now $myDate = "2008/07/25", how to add 3 days to it and then show 2008/08/28?

 

$num_loop = 9; // number of loops
for ($looped=0;$looped<$num_loop;$looped++) {
$date_array[$looped] = date("Y/m/d" , strtotime("+$looped days") );
// the array of date start from today & run for $num_loop times
}

PHP:

$date_array will be the array

For your another question:
you mean add a month also? it will be:

$three_days_n_one_month_later = strtotime("+3 days + 1 month"); //timestamp

// get it in date form
$newdate = date("Y/m/d",$three_days_n_one_month_later);

//print it
print $newdate;

PHP:

 

No, I mean if I only know $myDate, how do I know 3 days later of $myDate? For example, if I knew $myDate = 2008/07/25, how to add 3 days to $myDate and make it show 2008/07/28.

 

$num_loop = 9; // number of loops
for ($looped=0;$looped<$num_loop;$looped++) {
$date_array[$looped] = date("Y/m/d" , strtotime("+$looped days") );
// the array of date start from today & run for $num_loop times
}

PHP:

$date_array will be the array

$date_array[3] will be 3 days later

 

Since date("Y/m/d") will get the date of today, not a specified date (maybe a date in past or in future). For example I will record a date as $myDate, and I want to add 3 days to $myDate to get the date of 3 days later after $myDate. How to do that?

 

just add the date into the strtotime() the like below:

$date_later = strtotime("2008/10/21 +3 days + 1 month"); //in timestamp

// get it in date form
$newdate = date("Y/m/d",$date_later);

PHP:

or

$originaldate = '2008/10/21';
$date_later = strtotime("$originaldate +3 days + 1 month"); //in timestamp

// get it in date form
$newdate = date("Y/m/d",$date_later);

PHP:

and finally the array form you want:

$num_loop = 9; // number of loops
$originaldate = '2008/9/27';
for ($looped=0;$looped<$num_loop;$looped++) {
$date_array[$looped] = date("Y/m/d" , strtotime("$originaldate +$looped days") );
}

PHP:

the array above is limited to num of loops
this function below can do for any date (controllable future or past), maybe its a long step =.=

function getthedate($now,$changein_day,$pom_day,$changein_month,$pom_month) {
// $now in the form : 2008/8/17
/* the script below doesn't work =.=  why?
if ($changein_day >= 0) {$day = '+'.$changein_day;} elseif ($changein_day < 0) { $day = '-'.$changein_day; }
if ($changein_month >= 0) {$month = '+'.$changein_month;} elseif ($changein_month < 0) { $month = '-'.$changein_month; }
$changed_ts = strtotime("$now $day days $month months"); //in timestamp
$newdate = date("Y/m/d",$changed_ts);
*/
if ($pom_day == '-') { $pom_day = '-'; } else { $pom_day= '+';}
if ($pom_month == '-') { $pom_month = '-'; } else { $pom_month= '+';}
$changed_ts = strtotime("$now $pom_day $changein_day days $pom_month $changein_month months"); //in timestamp
$newdate = date("Y/m/d",$changed_ts);
return $newdate;
}

print getthedate('2008/5/5',10,'+',1,'-'); // + 10 days - 1 month
// getthedate('2008/5/5',1,'-',10,'-'); // - 1 day - 10 month
// getthedate('2008/5/5',5,'+',50,'+'); // + 5 day + 50 month

PHP:

 

Another way to do this is by knowing that strtotime() accepts a 2nd argument used as the offset timestamp. The default is of course time() (meaning now) so if you passed strtotime($myDate) as the 2nd argument then it would do the day increase to that one.

strtotime("+3 days", strtotime($myDate)) would add 3 days to the $myDate timestamp. Just seems a bit cleaner to me than strtotime("$myDate +3 days") for some reason. Not sure of its efficiency though since it's calling that function twice.

 

Thanks all, I tried $incDate=strtotime("$startDate + 3 days"); plus date("Y/m/d", $incDate); and it's working.

 

Thnx for sharing this tip bro