How to Extract <img src> from html using php ?

Hi

I've this code

<a href="http://google.com"><img border="0" src="http://www.google.co.in/intl/en_com/images/logo_plain.png">

Code (markup):

I want to get the src="" part of the above line and then update the entire code with

<a rel="lightbox" href="http://google.com"><img border="0" src="http://www.google.co.in/intl/en_com/images/logo_plain.png">

Code (markup):

How this can be done using php ?

 

Not sure if this is what your looking for ?

$find_src = preg_replace('#src="(.*?)"#','src="replace with this new image"',$find_src);

echo $find_src;

PHP:

Anything between the two ## will be replaced with src="replace with this new image"

 

No. This is not what I actually want.

I just want to add

to the <a href> tag immediate after the <a.
But note that , I need to add this line only if the <a tag is for <img>

That is

<a href="url> <img src="pic.png"></a> - > I need to add

<a href="url> Some text </a> -- > I don't need to add

 

Not really

I want to add that line to <a> tag, not <img >

Like

<a rel="lightbox" href="url> <img src="pic.png"></a> - > I need to add

Code (markup):

 

What effect would it have if the rel="lightbox" was added to normal text links ?

$find_href = preg_replace('#<a href="#','<a rel="lightbox href="',$find_href);

echo $find_href;

PHP:

 

No, this is not the one I wanted.

Add rel="lightbox" only if it is for IMG tag

 

Download your database and do a find & replace, then star fresh writing skills. Otherwise its impossible to archive what you want.

 

maybe this

$linkWithimg = '<a href="url"><img src="pic.png"></a>';
if (preg_match("/<img src=/i", $linkWithimg)) {
	$final = str_ireplace("<a href=", '<a rel="lightbox" href=', $linkWithimg);
	echo $final;
	}

PHP: