How to determine and show content?

I've got this string:
/comp.php?section=view&drawing=68&title=1234
How do I show the title output in php? So that it shows up in:
$title .= $model_name;
- the title field is called comments in a table...
A previous one that worked was:

} elseif ($_GET["blogID"] != "") { $query = "SELECT * FROM blog_sets WHERE setslug = '".mysql_real_escape_string($_GET["blogID"])."'"; $result = doQuery($query); $row = mysql_fetch_array($result); $model_name = $row["title_meta"]; $title .= $model_name;
 
}

Code (markup):

 

Is the task to change source-field id a database from "title meta" to "comments"?
Then the code will be next:

} elseif ($_GET["blogID"] != "") {
    $query = "SELECT * FROM blog_sets WHERE setslug = '".mysql_real_escape_string($_GET["blogID"])."'";
    $result = doQuery($query);
    $row = mysql_fetch_array($result);
    $model_name = $row["comments"];
    $title .= $model_name;
}

Code (markup):

 

Thanks, I think the code I gave isn't relevant. I just wanted to work out how to code if I've got the terms:
section=XX&drawing=XX&title=XX ?

Thanks