Hi there. I have been working on the following code: (I didn't know if there was a tag for asp, so i just used the one there is for php). <% response.buffer=false %> <html><body> <% dim land(30) dim antal(30) dim used(30) dim rest(30) dim i rest(0) = 345 land(0)="D" antal(0)=29 used(0)=0 rest(1) = 316 land(1)="F" antal(1)=29 used(1)=0 rest(2) = 287 land(2)="GB" antal( 2)=29 used(2)=0 rest(3) = 258 land(3)="I" antal(3)=29 used(3)=0 rest(4) = 229 land(4)="E" antal(4)=27 used(4)=0 rest(5) = 202 land(5)="PL" antal(5)=27 used(5)=0 rest(6) = 175 land(6)="RO" antal(6)=14 used(6)=0 rest(7) = 161 land(7)="NL" antal(7)=13 used(7)=0 rest(8) = 148 land(8)="GR" antal(8)=12 used(8)=0 rest(9) = 136 land(9)="P" antal(9)=12 used(9)=0 rest(10) = 124 land(10)="B" antal(10)=12 used(10)=0 rest(11) = 112 land(11)="CZ" antal(11)=12 used(11)=0 rest(12) = 100 land(12)="H" antal(12)=12 used(12)=0 rest(13) = 88 land(13)="S" antal(13)=10 used(13)=0 rest(14) = 78 land(14)="A" antal(14)=10 used(14)=0 rest(15) = 68 land(15)="BG" antal(15)=10 used(15)=0 rest(16) = 58 land(16)="DK" antal(16)=7 used(16)=0 rest(17) = 51 land(17)="SK" antal(17)=7 used(17)=0 rest(18) = 44 land(18)="FIN" antal(18)=7 used(18)=0 rest(19) = 37 land(19)="IRL" antal(19)=7 used(19)=0 rest(20) = 30 land(20)="LT" antal(20)=7 used(20)=0 rest(21) = 23 land(21)="LV" antal(21)=4 used(21)=0 rest(22) = 19 land(22)="SLO" antal(22)=4 used(22)=0 rest(23) = 15 land(23)="EST" antal(23)=4 used(23)=0 rest(24) = 11 land(24)="CY" antal(24)=4 used(24)=0 rest(25) = 7 land(25)="L" antal(25)=4 used(25)=0 rest(26) = 3 land(26)="M" antal(26)=3 used(26)=0 dim count dim overTwenty overTwenty = 0 function mytry(byref n,byref sum) dim i dim str dim x x = 0 if (sum=255) then count = count+1 ' response.write("<br>#" & count & ": ") for i=0 to n-1 if (used(i)=1) then str = str & land(i) & "(" & antal(i) & ") " x = x+1 ' response.write(land(i) & "(" & antal(i) & ") ") end if next if (x>=20) then response.write("<br><strong><font COLOR='green'>+</font></strong> #" & count & ": " & str & " = " & sum &"") overTwenty = overTwenty + 1 else response.write("<br><strong><font COLOR='red'>x</font></strong> #" & count & ": " & str & " = " & sum &"") end if else if (n<27) then ' dim newnum ' newNum = n+1 if (sum + rest(n) > 254) then if (sum + antal(n) < 256) then used(n)=1 count = mytry(n+1,sum+antal(n)) end if used(n)=0 count = mytry(n+1,sum) end if end if end if mytry = count end function response.write("<i>Bemærk: Programmet følger ikke korrekt matematisk notation, dette har noget at gøre med måden hvorpå programmet behandler sine data. Således er et '+' imellem hvert land underforstået, samtidigt med at forkortelsen foran tallet er tiltænkt som en hjælp til lettere at forstå udregningen.</i><br><br>Udregning påbegyndes/" ) i = mytry(0,0) response.write("<br>/Udregning tilendebragt<br><br><strong>Resultater:</strong>") response.write("<br>Kombinationer hvori det dobbelt kvalificerede flertal overholdes: "& overTwenty &"") %> </body> </html> PHP: (Don't mind the Danish in the code). What it does is that at finds all combanations of the countries that gives exactly 255. Afterwards it finds all combinations in which there are 20 or more countries represented, and count them in the end. What I need to do is to count how many combinations in which there are 20 or more countries represented, that has both the country DK and the country F in them. I can't quite figure out how to do this, so i am asking you for help. Thx Eirik-