How to choose either source1 or source2

Hi

I am trying to display either source1 or source2 thumbnail image but unable to find a solution. Hopefully someone will be able to help.

Here is the code I am trying to figure out.

$db=mysql_connect ($DB_HOST ,$DB_USER,$DB_PASSWORD) or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db ($DB_NAME);
$num_rows = mysql_num_rows(mysql_query("select * from project"));
$result = mysql_query($query) or die ('Query Error: ' . mysql_error());

header("Content-Type: text/xml");
header("Expires: 0");
print "<?xml version=\"1.0\" encoding=\"UTF-8\" ?>\n";
print "<ut_response status=\"ok\">\n";

print "<project_list>\n";

while ($results = mysql_fetch_array($result))
{
	$viewnumber = $results['Views'];
	$title = $results['title'];
	$viewkey = $results['screen'];
	$code = $results['thumbnail'];

  preg_match('(file=[\"a-z:\/\.\?=\-0-9A-Z_\"]*)',$code,$results);
  $file = substr($results[0],5,strlen($result[0])-4);
  $source1 = $file;


  preg_match('(src=[\"a-z:\/\.\?=\-0-9A-Z_\"]*)',$code,$results);
  $src = substr($results[0],5,strlen($result[0])-1);
  $source2 = $src;

print "<project>\n";

print "<views>";
print "$viewnumber";
print "</views>\n";

print "<title>";
print "$title";
print "</title>\n";

print "<url>";
print "$viewkey";
print "</url>\n";

print "<thumbnail_url>";
print "$source1";
print "</thumbnail_url>\n";

print "</project>\n";

}
mysql_close();

print "</project_list>\n";

print "</ut_response>";

Code (markup):

This code works to display thumbnail from source1. How can I make it to display source2?

Any help is greatly appreciated.