I am wondering how many 3 letter/number domains would be out there altogether? Also how many 2 letter/number domains? Is there anyone who got Maths degree? I would appreciate you could calculate it. thank you
Rythm, that's incorrect.. You don't need a maths degree but you do have to remember stuff from high school. You're looking at permutations here. for 3 letter domains there are 15600 possible combinations. For 2 letters there are 650
oh, you wanted numbers AND letters. for 3 letters/number combinations there are 39270 for 2 letters/number combinations there are 1190
That's not true, you can use a letter/number as often as you'd like. Why wouldn't it be possible to have the domain aaa.com? Also, there are 10 different numbers and not 9 as you used in your calculation. So that's 36^3 = 46656 combinations of 3 character domain names (hyphens excluded). And 36^2 = 1296 different 2 character domain names.
Oh yeah... I forgot 0 was a number ^_^; ok, so here it is again, with repetition enabled (of course a domain can be aaa.com.. silly me). in this case it's even easier. Just use n to power of r 3 characters = 46656 2 characters = 1296
OK people. I don't know why you still wondering about the combinations but these are the right ones : 2 characters ONLY letters = 676 2 characters TOGETHER with numbers = 1,296 3 characters ONLY letters = 17,576 3 characters TOGETHER with numbers = 46,656 Not calculating the dashes
allowed characters in a domain name a-z 0-9 as well as a - provided it doesn't start or end the name the name 36^3=46656 36^2=1296 46656=1296= 47952 3 letter combinations including dashes 36^2=1296 2 letter combinations 267 available tld's so... 12,803,184 3 letter domains as to the number of 2 letter domains. it will be less than 346032 as many tlds don't allow them to be registered some of those that do require one of the characters to be a number... so forth and so on... which would require more work to figure out than I want to put into it.
Are you talking about all the combos including the ccLTD ones as well. If so, all the above posters are incorrect