How can send the value of a variable from page to another page

Hello everybody

At first i have 2 php page

The first page get the (id,name, sorting) of the sections from database
The second page Receiving the data (id,name, sorting) to editing or deleting from database

in the first page every section has id number to distinguish between each section and the other

I want to do is send section ids and other data to second page by Ajax
and I am already do it so successfully but i have One problem

Receive all the sections are single id

Example
section1 -- id(20)
section2 -- id(15)
section3 -- id(33)
section4 -- id(71)

i'm Receiving all the sections id are id(33)
i have used session and hidden field but Occurs with the same problem


The first PHP page code (get the (id,name, sorting) of the sections from database)

<table id='tab' class='sty' border='1' cellpadding='5' cellspacing='5'>
            <tr>
                <td>
                    Order
                </td>
                <td>
                    Section Name
                </td>
                <td>
                    Editing
                </td>
            </tr>
            <?php
            $get = mysql_query("select * from cat");
            while ($row = mysql_fetch_array($get)) {
                //echo "<form action='page4.php' method='POST'>";
                echo "<tr><td>";
                echo "<input type='text' name='sec_sort' id='sec_sort' value='".$row['sorting']."' size='1' />";
                echo "</td><td>";
                echo "<input type='text' name='sec_name' id='sec_name' value='".$row['catname']."' />";
                echo "</td><td>";
                echo "<input type='button' name='edit_name_button' id='edit_name_button' value='Edit' onclick='edit_section()' />";
                echo "</td></tr>";
                echo "<input type='hidden' name='getid' id='getid' value='".$row['catid']."' />";
                //echo "</form>";
            }
            ?>
        </table>

PHP:

The second PHP page code (Receiving the data (id,name, sorting) to editing or deleting from database)

<?php
        $sec_sort = $_POST['sec_sort'];
        $sec_name = $_POST['sec_name'];
        $getid = $_POST['getid'];
        
        if ( isset ($_POST['edit_name_button'])) {
            $edit_sec = mysql_query("update cat set catname='$sec_name',sorting='$sec_sort'  where catid='$getid'");
            if ($edit_sec) {
                echo $getid;
                echo "the data has been updated";
            }
            else {
                echo $getid;
                echo "Error, no data is updated";
            }
        }
?>

PHP:

The ajax code (Which sends the data id,name, sorting to page 2)

function edit_section(){
    var sec_sort = document.getElementById('sec_sort').value;
    var sec_name = document.getElementById('sec_name').value;
    var edit_name_button = document.getElementById('edit_name_button').value;
    var getid = document.getElementById('getid').value;
    
    
    Http.onreadystatechange = function(){
        if (Http.readyState == 4) {
            document.getElementById('result').innerHTML = Http.responseText;
        }
        
        else {
            document.getElementById('result').innerHTML = "loading";
        }
    }
    
    
    url = "sec_sort=" + sec_sort + "&sec_name=" + sec_name + "&edit_name_button=" + edit_name_button + "&getid=" + getid;
    Http.open("POST", "page4.php", true);
    Http.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    Http.send(url);
}

Code (markup):

I explained the problem in detail

I wish help from all
​