Help with one line of php

Hy guys,
I want to make a redirect.php page.
I want to make it like this :
redirect.php?url=http://site.com
So when you enter that url it redirects to http://site.com

What's the piece of code to use ?
I tried this but it's not working :

<?php header("Location: $_GET['$url']"); ?>

PHP:

Can you help me please ? Thanks

 

<?php
header( 'Location: http://www.yoursite.com/new_page.html' ) ;
?>

please try this

 

Thanks, but that's not what i need.
I want it to dynamic redirect to any url you enter after ?url=

 

<?php
header( 'Location: $url' ) ;
?>

please give it a try

 

Nope, not working, I asked a friend he gave me the code, and it's working :

<?php
$u=$_GET['url'];
echo "
<script>window.location='".$u."'</script>
";

?>

PHP:

Thanks anyways for your time
rep added

 

Great it is fine

 

<?php header("Location: $_GET['$url']"); ?>

PHP:

doesn't work because you have an array in the double quoted string: normal variables can be done like that, but not array items (reliably).

<?php
header( 'Location: $url' ) ;
?>

PHP:

won't work because you have a variable in a single quoted string: single quoted strings aren't parsed for variables.

What you were looking for, really, is something like:

<?php 
header('Location: ' . $_GET['$url']); 
?>

PHP:

Hope that helps for the future...

 

Hmm your code won't work, showing me a blank page... thanks anyway...

 

God, got to say...NOOBS. Anyway:

<?PHP
die(header("location: ".$_GET['url']));
?>

There...That will work, enjoy!

 

The reason this isn't working for you is because you're using a variable (or trying to) inside the GET.

$_GET["$url"] will never work. It has to be $_GET["url"].

 

Ah crap, my bad... absolutely right guys. Sorry, just a little too much copy and pasting on my behalf...

 

<?php header('Location: '.$_GET['url']); die('Go to '.$_GET['url']); ?>

PHP:

Why was this thread SO long? , I would've made it a hyperlink but I'm lazy.

 

You can use arrays inside double quotes ...

<?php header("Location: {$_GET['url']}"); ?>

PHP: