Help with debug

part of a larger function, echo.

function doOpen(url)
{
var popURL = "about:blank"
var popID = "'ad_'" + Math.floor(89999999*Math.random()+10000000);
var pxLeft = 0;
var pxTop = 0;
pxLeft = (GetWindowLeft() + (GetWindowWidth() / 2) - (PopWidth / 2));
pxTop = (GetWindowTop() + (GetWindowHeight() / 2) - (PopHeight / 2));

if ( puShown == true )
{
return true;
}

Code (markup):

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /filepath.php on line 61

 

function doOpen(url){var popURL = "about:blank";var popID = "'ad_'" + Math.floor(89999999*Math.random()+10000000);var pxLeft = 0;var pxTop = 0;pxLeft = (GetWindowLeft() + (GetWindowWidth() / 2) - (PopWidth / 2));pxTop = (GetWindowTop() + (GetWindowHeight() / 2) - (PopHeight / 2));if ( puShown == true ){return true;

PHP:

 

If you didn't catch it, echipvina was trying to point out that you forgot a semicolon after:

var popURL = "about:blank"

Code (markup):

 

If your saying that it should read like this

function doOpen(url)
{
var popURL = "about:blank";
var popID = "'ad_'" + Math.floor(89999999*Math.random()+10000000);
var pxLeft = 0;
var pxTop = 0;
pxLeft = (GetWindowLeft() + (GetWindowWidth() / 2) - (PopWidth / 2));
pxTop = (GetWindowTop() + (GetWindowHeight() / 2) - (PopHeight / 2));

if ( puShown == true )
{
return true;
}

Code (markup):

i had tried that already. brings up same error. same line.

 

The code you write is javascript. if you put that between <?php and ?> it will not work.
You will need to put the javascript between the tags <script language="javascript"> and </script>
and if you want to add javascript between <?php and ?> you will need to echo it.

 

Yes, possible.

I tried changing <script> to <script type=\"text/javascript\"> (it is already within a <script> </script> inside the larger php file that encompasses it but also tried changing script to the line above is what I am trying to say)

It is part of a *.php file that I am wanting to upload to wordpress which is why its included also in larger <?php

 

ANd its echoed before a previous function.

function StartsLikeThis(){
    
    echo "
    <script type=\"text/javascript\">

Code (markup):

 

It is unpossible to check for us if we not have the code.

 

change this
var popURL = "about:blank"
to this
var popURL = "about:blank";

 

Please read the comments before posting. I've just read three of your comments in the last minute that were all deemed useless because your responses were wrong or repeats.