Hi, My code looks like this: <li id="id_5" value="5"> <select id="cat_5" class="dropdown" name="cat_5"> <option value="1">one</option> <option value="2">two</option> <option value="3">three</option> <option value="4">four</option> <option value="5">five</option> <option value="6">six</option> <option selected="selected " value="7">seven</option></select> <li id="id_6" value="6"> <select id="cat_6" class="dropdown" name="cat_6"/> </select> Now I would like to copy all 7 options into the new select (id="cat_6). Can someone please tell me how can I do that?? Thanks in advance. suami.
Hi suami, I suppose, from your example, it should copy the options to cat_6 after you select one from cat_5, right? Then add onchange event here : <select id="cat_5" class="dropdown" name="cat_5" onchange="copyThem(this, 'cat_6')"> And the function could be like this : function copyThem(from, to_id) { var ind = from.selectedIndex, to = document.getElementById(to_id), copy; for(var i=0; i<=ind; i++) { copy = from.options; to.options = new Option(copy.text, copy.value); } } It depends much on what you gonna do with it, because the example I gave you doesn't clean options in the cat_6 (when selecting option from cat_5 twice), it copies all options till and with the selected one... But I hope you can get some idea, how to adapt it to your needs.