Help With an If/Else Statement Pelase

Hi there,

I need to make an if/else statement and I'm stumped.

Here's what I want the code to do:
If what's in my row starts with "http://" then use a certain code.
Else, use a another code.

Kind of like this:

<?
if (CODE TO USE IF THIS ROW CONTAINS "HTTP://")
then display this: <img src="<?php echo "{$row[picfile]}"; ?>">

else:
<?php

if (@mysql_num_rows($pres))
{
	$i = 0;
?>

	<table class="adpics" width="100%"><tr><td>

<?php
	while ($row = mysql_fetch_array($pres))
	{
		$i++;

		$imgsize = GetThumbnailSize("{$datadir[adpics]}/{$row[picfile]}", $images_max_width, $images_max_height);

?>

<img src="<?php echo "{$datadir[adpics]}/{$row[picfile]}"; ?>">

<?php
	}
?>

	</td></tr></table>

<?php

	$imgcnt = $i;

}
?>

Code (markup):

As you can see, the only difference really is this code here: <img src="<?php echo "{$datadir[adpics]}/{$row[picfile]}"; ?>">

Any help would be appreciated. Thank you.

 

Which will storage content for "If what's in my row starts with "http://" then use a certain code. " ? If this is variable , using :

$string;

if($string == "http://")
{
// do
}
else
{
//do
}

 

Thanks for the reply anhbloginc, much appreciated.

The storage is actually being called from {$row[picfile]}
In the picfile column in mysql it can contain either a whole url to a picture or the picture name.

So, in the if, I need to say if {$row[picfile]} starts with http:// then display my code.
Else, display another piece of code.

I hope I explained it right. Thanks again.

 

www.php.net/preg_match

 

Thanks K1llswitch, unfortunately, it looks like chinese to me.

But, thanks for the thought.

 

don't use preg_match that's a waste...

<?php
if(substr($row['picfile'], 0, 7) == 'http://')
{
#yep do something here
}

else{
#nope do something else
}
?>

PHP: