Help: Simple form/php multiple buttons...

I have this code which is like a double or nothing game...

And if its heads an option comes up (a button) to take your winnings, -or the original button which will bet again...

The problem is,

The second button resets the whole form, -and does not update values/execute php...

Can anyone suggest a fix to this? or how i can get this working?

<form id="form1" name="form1" method="post" action="">
<input type="submit" name="Submit" id="Submit" value="Play" />
</form>
<?
if (isset($_POST['Submit'])) {
echo "You pay the man $10 and watch as he flips the coin..." ."<br>";
$coin = (rand()%2);
if ($coin == 0) {
echo "It lands on heads," . "<br>";
$bet = $bet * 2;
echo "You are now betting $". $bet ."<br>";
mysql_query("UPDATE Doubleornothing SET Money = '$bet' WHERE Username = '$username'");
?>
<form id="form2" name="form2" method="post" action="">
<input type="submit" name="Submit2" id="Submit2" value="Take winnings" />
</form>
<?
if (isset($_POST['Submit2'])) {
echo "You take your $". $bet;
mysql_query("UPDATE Zombie SET Money = Money '$bet' WHERE Username = '$username'");
mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
}
}
if ($coin == 1) {
echo "It lands on tails," . "<br>";
echo "You lose everthing..." . "<br>";
mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
}
}

Thanks alot,

James

 

It should be something like this

<?
if ($_POST['action'] == "Play")
{
	echo "You pay the man $10 and watch as he flips the coin..." ."<br>";
	$coin = (rand()%2);
	if ($coin == 0) {
		echo "It lands on heads," . "<br>";
		$bet = $bet * 2;
		echo "You are now betting $". $bet ."<br>";
		mysql_query("UPDATE Doubleornothing SET Money = '$bet' WHERE Username = '$username'");
     }
	 if ($coin == 1) {
		echo "It lands on tails," . "<br>";
		echo "You lose everthing..." . "<br>";
		mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
	}
}
if ($_POST['action'] == "Take winnings"){
	echo "You take your $". $bet;
	mysql_query("UPDATE Zombie SET Money = Money '$bet' WHERE Username = '$username'");
	mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
}
	
	

?>
<form id="form1" name="form1" method="post" action="">
<input type="submit" name="action" id="Submit" value="Play" />
<input type="submit" name="action" id="Submit2" value="Take winnings" />
</form>

Code (markup):

 

I think you have to put form action. Also check the update query.

mysql_query("UPDATE Zombie SET Money = Money '$bet' WHERE Username = '$username'");

PHP:

It should be like this

mysql_query("UPDATE Zombie SET Money = '$bet' WHERE Username = '$username'");

PHP:

 

It sort off works, I want it so the Play button is before the game text, -and the 'Take winnings' button only appears after there is some winnings -on mine, after one heads.

Anyone suggestions?

 

Try this

<?
<form id="form1" name="form1" method="post" action="">
if ($_POST['action'] == "Play")
{
	echo '<input type="submit" name="action" id="Submit" value="Play" />';
	echo "You pay the man $10 and watch as he flips the coin..." ."<br>";
	$coin = (rand()%2);
	if ($coin == 0) {
		echo "It lands on heads," . "<br>";
		$bet = $bet * 2;
		echo "You are now betting $". $bet ."<br>";
		mysql_query("UPDATE Doubleornothing SET Money = '$bet' WHERE Username = '$username'");
     }
	 if ($coin == 1) {
		echo "It lands on tails," . "<br>";
		echo "You lose everthing..." . "<br>";
		mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
	}
}
if ($_POST['action'] == "Take winnings"){
	echo "You take your $". $bet;
	mysql_query("UPDATE Zombie SET Money = Money '$bet' WHERE Username = '$username'");
	mysql_query("UPDATE Doubleornothing SET Money = '10' WHERE Username = '$username'");
}
?>

<? if ($bet > 0) { ?>
<input type="submit" name="action" id="Submit2" value="Take winnings" />
<? } ?>
</form>

Code (markup):