Help needed on AJAX with PHP

What is wrong with this code: I am getting any return values from PHP
Html code

<script type="text/javascript"> 
			var url = "AjaxCall.php"; // The server-side script
			 var xmlhttp;
			function handleHttpResponse() {   
				alert(6);
	        if (xmlhttp.readyState == 4) {
				alert(7);
				var results=xmlhttp.responseText;
				alert(results);
				if(xmlhttp.status==200) {
                  var results=xmlhttp.responseText;
				  alert(5);
				  alert(results);
				}
			  }
		    } 
			function requestCustomerInfo() {     
				//var sId = document.getElementById("txtCustomerId").value;
				xmlhttp = getHTTPObject();
				xmlhttp.open("GET", url, true);
				xmlhttp.onreadystatechange = handleHttpResponse;
				xmlhttp.send(null);
			}
			function getHTTPObject() {
			     
				  if(window.XMLHttpRequest){
					xmlhttp = new XMLHttpRequest();
				  }
				  else if (window.ActiveXObject){
					xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
					if (!xmlhttp){
						xmlhttp=new ActiveXObject("Msxml2.XMLHTTP");
					}
   				}
				return xmlhttp;
			} 
		</script>

Code (markup):

AjaxCall.php

<?php

echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
 echo "<tr>";
 echo "<td></td>";
 echo "</tr>";
echo "</table>";
?>

Code (markup):

 

I am not an expert on this, but don't you need to execute your AJAX functions first?

 

Your ajax code and initialization could be better.

I rewrote it:

function ajax()
{
	var url = "AjaxCall.php"; // The server-side script
	var xmlHttp;
	try // Firefox, Opera 8.0+, Safari
	{
		xmlHttp=new XMLHttpRequest();
	}
	catch (e) // Internet Explorer
	{
		try
		{
			xmlHttp=new ActiveXObject("MSXML2.XMLHTTP");
		}
		catch (e)
		{
			try
			{
				xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
			}
			catch (e)
			{
				alert("Your browser does not support AJAX!");
				return false;
			}
		}
	}
	xmlHttp.onreadystatechange=function()
	{
		if(xmlHttp.readyState==4)
		{
			alert(xmlHttp.responseText);
		}
	}
	xmlHttp.open("GET",url,true);
	xmlHttp.send(null);
}

PHP:

However just for your info you shouldn't use AJAX if all you want is a table.
This makes more sense:

alert("<table border='1'><tr><th>Firstname</th><th>Lastname</th><th>Age</th><th>Hometown</th><th>Job</th></tr><tr><td></td></tr></table>")

PHP:

 

Good One