help in php.

Discussion in 'PHP' started by cris02, Apr 25, 2008.

  1. #1
    hi i have a code here:
    
    <?php
        $query2 = "SELECT * FROM gold where reward_type='gold miles'";
        $result2 = mysql_query($query2);
        $counter = 0;
        while($info = mysql_fetch_array($result2)) {
        print "<table width='98%' border='1' align='center' cellpadding='0' cellspacing='0' bordercolor='#CCCCCC'>
          <tr>
            <td width=6%><input type='checkbox' name='checkbox".$info['rid']."' value=".$info['F3']."><input type='hidden' name=".$info['F3']." id='hide' value=".$info['F3']."></td>
            <td width=13%>".$info['F3']."</td>
            <td width=49%>".$info['p_name']."</td>
            <td width=8%>".$info['F6']."</td>
            <td width=8%>".$info['F7']."</td>
            <td width=8%>".$info['F8']."</td>
            <td width=8%>".$info['F9']."</td>
          </tr>
        </table>";
        }
    ?>
    
    PHP:
    which is loop on every record. now i want to display all the value of each checkboxes that i've checked on other page by submitting the form. in short i want to detect this name='checkbox".$info['rid']."' on the other page, which is ".$info['rid']." is a autonumber came from databse. anyone can help,, thanks in advance.
     
    cris02, Apr 25, 2008 IP
  2. kmap

    kmap Well-Known Member

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    #2
    Did u made a form?

    if yes then


    <?php $query2 = "SELECT * FROM gold where reward_type='gold miles'"; $result2 = mysql_query($query2); $counter = 0; while($info = mysql_fetch_array($result2)) { print "<table width='98%' border='1' align='center' cellpadding='0' cellspacing='0' bordercolor='#CCCCCC'> <tr> <td width=6%>".$_POST['checkbox'.$info['rid']]."</td></table>";

    ?>
     
    kmap, Apr 26, 2008 IP