Help in multiple if else.

Hello frnds i am using mutiple and conditions in if.but i am having problem.i have in adminaproval variable=0;but it doesnt chek its condition.its still goes to last if else.which has adminapproval=1;
//////////////////////////////////////

<?php
include('../../includes/DB.class.php');
$name = $_POST['txt_name'];
$password = $_POST['txt_password'];
//echo "$name";
//echo "$password";
//getch();
//public function user_Exist($name,$pswd){
require('Login_DAO.class.php');
$login_dao=new LoginDAO();
$returnarray=$login_dao -> user_Exist($name,$password);
$i=$returnarray[0];
$usertype=$returnarray[1];
$adminApproval=$returnarray[2];

echo "usertype=$usertype \t";
echo "adminApproval=$adminApproval\t";

if($i == 0)
{

$_SESSION['msg'] = "Wrong Username or &nbsp;Password";
getch();
header("Location:../index.php");
}
else if($i == 1 && $usertype == 'Admin')
{
session_start();
$sessionid=session_id();
echo "$sessionid";
//$maxRegId = mysql_fetch_array($result);
$_SESSION['id'] = $sessionid;
header("Location:../../../../in-admin-panel/index.php");
}

else if($i == 1 && ( $adminApproval='0' && $usertype == 'Seller'))
{
echo "Wait For Admin Aproval";
getch();
}
else if($i == 1 && ($usertype == 'Seller' && $adminApproval='1'))

{

session_start();
$sessionid=session_id();
echo "$sessionid";

//Ine No=70
getch();
header("Location:../../Seller/myshop.php");

}

//}
//}
?>



////////////////////////////////////////////////////////////////////
OutPut

usertype=Seller adminApproval=0 seshion id=6t50e31cf3em7l8np4cth47791
Fatal error: Call to undefined function getch() in C:\wamp\www\architecturedataforebazaradminviewscreenshot\Final_EBazar\Final_EBazar\admin\classes\Login_BL.class.php on line 70
/////////////////////////////////////////////////////////////////////////////
its going on 4th else if.it should be in 3rd.
Help me.

 

First of all .... you do not have a function called getch() defined... that's why you get fatal error
Second...

After this line:
$returnarray=$login_dao -> user_Exist($name,$password);

add the code below:

var_dump($returnarray);
die;

And place the output here

 

Dear:
Thanks For Replying.
I want to explain you something first.i am not talking about Error.i am using getch() For Debuging.Ant it tells me where does execution Goes.
and i have Recieved the array corctly.and i have printed it well.and it is correct.
a am reciving in $adminaproval=0; which corect.
But my execution still goes in 4th If condition.which is
else if($i == 1 && ($usertype == 'Seller' && $adminApproval='1')){

}
i ahve $adminApproval=0.which is corectly printed above.


i am sending code again:


////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////

<?php


include('../../includes/DB.class.php');

$name = $_POST['txt_name'];
$password = $_POST['txt_password'];

require('Login_DAO.class.php');
$login_dao=new LoginDAO();

$returnarray=$login_dao -> user_Exist($name,$password);

$i=$returnarray[0];
$usertype=$returnarray[1];
$adminApproval=$returnarray[2];

echo "usertype=$usertype \t";
echo "adminApproval=$adminApproval\t";

if($i == 0)
{

$_SESSION['msg'] = "Wrong Username or &nbsp;Password";
getch();
header("Location:../index.php");
}
else if($i == 1 && $usertype == 'Admin')
{
session_start();
$sessionid=session_id();
echo "$sessionid";
$_SESSION['id'] = $sessionid;
header("Location:../../../../in-admin-panel/index.php");
}


else if($i == 1 && ( $adminApproval='0' && $usertype == 'Seller'))
{
echo "Wait For Admin Aproval";
getch();
}
else if($i == 1 && ($usertype == 'Seller' && $adminApproval='1'))
{
session_start();
$sessionid=session_id();
echo "$sessionid";
$_SESSION['id'] = $sessionid;
getch();
header("Location:../../Seller/myshop.php");

}


?>

/////////////////////////////////////////////////////////////////////////////////////////////////////////////
printing:
usertype=Seller, adminApproval=0 //output of variables

Fatal error: Call to undefined function getch() in C:\wamp\www\architecturedataforebazaradminviewscreenshot\Final_EBazar\Final_EBazar\admin\classes\Login_BL.class.php on line 50

my execution still going in that if condition in adminApproval=1;But i actually have adminApproval=0;

i hope so now you get understating what i am having problem actually.
Thanks

 

I can't help until I see the values of the parameters in returnarray .... so again:

After this line:
$returnarray=$login_dao -> user_Exist($name,$password);

add the code below:

var_dump($returnarray);
die;

And place the output here

 

Sir i am telling values in parameters from Return array are these which i am printing above.

usertype=Seller, adminApproval=0,i=1 //output of variables from Return Array.

Values are correctly recieved and printed above.
//////////////////////////////////////////////////////////////////////////////////////
And After Using:


$returnarray=$login_dao -> user_Exist($name,$password);

var_dump($returnarray);
die;

///////////////////////////////////////////////////////////////////
Output is:
array(3) { [0]=> string(1) "1" [1]=> string(6) "Seller" [2]=> string(1) "0" }

////////////////////////////////////////////////////////////////
i think this is hapening.
First Index [0]=i=1 //i value=1
2nd Index [1]=usertype=Seller//value
3rd Index [2] =adminapproval=0//

so now what you say?

 

According to these parameters

array(3) { [0]=> string(1) "1" [1]=> string(6) "Seller" [2]=> string(1) "0" }

i = 1, usertype = seller, adminapproval = 0

so based on the parameters above script should not match any ifs... BUT

it goes to number 4 because of this line:

else if($i == 1 && ($usertype == 'Seller' && $adminApproval='1'))

which means
i == 1 => TRUE
AND
usertype == Seller => TRUE
adminApproval = 1 => TRUE (it is = not ==)

TRUE and TRUE evaluates TRUE

so I guess

$adminApproval='1' should be $adminApproval == 1

you are missing a comparision ==

I hope this helps

 

Thanks much sir.i was disturbing from Yesterday because of this careless ness.
i didnt saw that it was an single "=";

thanks once again