Help!Generating random number without the generated numbers already ??

can anyone hep me me make a function that return random numbers but it will not generate another random number if he already pass the value for example it return 2, so after i call the function random again it will not return another 2 i want another numbers to be returned instead ?? can anyone help me here?

function random($max){
srand ((double) microtime( )*1000000);
$random_number = rand(0,$max);
return $random_number;
}

 

I couldn't reproduce that issue using that code (on PHP 5.2)

mt_rand provides better random number by the way:

function random($max){
  return mt_rand(0,$max);
}

PHP:

Up to you if you still want to use the wrapper, I don't bother with one.

 

nice thx but how can i get the function to return numbers that are not alraedy returned?

 

Oh, I thought you meant the subsequent numbers were all the same instead of "they should never be the same".

function random($max) {
  static $numbers = array();
  do { $n = mt_rand(0, $max); }
  while (in_array($n, $numbers));
  return $numbers[] = $n;
}

PHP:

 

nice one thx very much really appreciate your help