help exactly matching one element in a multi-element field

I have a field with numbers separated by '|' like 9|10|106|26|

What I need to do is check to see if just one of those numbers is an exact match to a variable $userid and if it is print something.
Obviously 10 would need to match whereas 106 does not....or...in other words 26 is different than 226....( I hope you guys get what I mean if not I'll try to explain better)


Here is the NON working code I have so far:

$getids =mysql_query("select numbers from users where Username='$username'; ") or die ("could not get id info");
$idstotal = mysql_fetch_array($getids);

$idnums = explode('|',$idstotal['numbers']);

foreach(explode('|',$idstotal['numbers']) as $value) {
   if($value == $userid) {
$i ='[F]';
   }
else {
$i ="[A]";
}
}

echo $1;

Code (markup):

So far it does not work because $userid never matches because the numbers come out all together as one single number. I just can't figure out how to get them all to be compared individually.

Can you guys help me to get it to work?

 

You don't need to put explode('|',$idstotal['numbers']); as a condition in foreach, as you already defined a variable for that. I replaced it with $idnums.
Also, the last row said echo $1;, although you stored F/A in $i - fixed that too

EDIT: Found another thing... the code would only have worked if the matching element is the last element in the list. So, when you find a match, you have to break the loop. Otherwise $i would be overwritten and your result is lost. => I added a break to the code.

$getids =mysql_query("select numbers from users where Username='$username'; ") or die ("could not get id info");
$idstotal = mysql_fetch_array($getids);

$idnums = explode('|',$idstotal['numbers']);

foreach($idnums as $value) {
   if($value == $userid) {
      $i ='[F]';
      break;
   }
   else {
      $i ="[A]";
   }
}

echo $i;

PHP:

 

How about:

$i = in_array($userid, $idnums) ? '[F]' : '[A]';

PHP:

 

Great! Thanks guys..........