Hey guys i have a php form like so, <?php include('auth.php'); include('database_access_param.php'); $db_link=mysql_connect($hostname, $dbuser, $dbpassword) or die("Unable to connect to the server!"); $quesid=1; mysql_select_db($dbname) or die("Unable to connect to the database."); $cat=movie; $totalCorrect=0; $ssql="select * from quiz where cat='".$cat."'"; //echo $ssql."<br>"; $sresult=mysql_query($ssql); print('<html>'); print('<table class="report" width="50%" border="1" align="center" cellpadding="2" cellspacing="1"'); print('<body><br><br>'); print('<head><title>Movies Category</title>'); print('<form action="ha.php" method="post" onSubmit="return checkme()">'); print('</head>'); if(mysql_numrows($sresult)) { print('<tr><th>QuizId:</th><th>QuizTopic:</th><th>PlayGame:</th></tr>'); while($row = mysql_fetch_row($sresult)) { $qid = $row[0]; $Quiz_Topic = $row[1]; $cat= $row[2]; $score= $row[3]; echo'<tr><td>'.$qid.'</td><td>'.$Quiz_Topic.'</td><td align=center><a href="index.php?qid='.$qid.'&quesid='.$quesid.'&Quiz_Topic='.$Quiz_Topic.'&totalCorrect='.$totalCorrect.'&boxaction=PlayGame">Play Game</a></td></tr>'; } } else { print('<tr><th colspan=3>No Record Found!</th></tr>'); } print('</body>'); print('</html>'); print('</table>'); i was wondering how youd go about passing the values where the playgame is to a new script that opens a windon pop-up thatll contain the values passed fromt his script.thanks