Going on 2nd Day...

This is the code:

$SQL="Select * From ProjectText Where ProjectID = $ProjectID";
$Texts= mysql_query($SQL);
while($Txt = mysql_fetch_array($Texts));
{
        $SQL="Select * From Texts Where TemplateID = $TemplateID and TextID = $Txt[1]";
        $result = mysql_query($SQL);
        $row = mysql_fetch_row($result);
        $PosLeft = $row[2]*$Inch; 
        $PosBottom = $row[3]*$Inch;
        $PosWidth  = $row[4]*$Inch;
        $PosHeight  = $row[5]*$Inch;
        $Font  = "Fonts/$row[6]";
        $Color  = $row[7];
        $Shadow = $row[8]; 
        //Create Cropped Overlay Image
        imagettftext($overlay , 36 , 0 , $PosLeft , $PosBottom, $red , $Font , $Txt[2]);
}

Code (markup):

This is the data:

ProjectID, TextID, Text 
127, 2, is a Test 
127, 1, This

ProjectID = VARCHAR
TextID = VARCHAR
Text =VARCHAR

Code (markup):

Why does $Txt[1] evaluate to "null"?

echoed SQL:

Select * From Texts Where TemplateID = $TemplateID. and TextID = 

Code (markup):

 

Use single quotes around varchar values. e.g.

$SQL="Select * From ProjectText Where ProjectID = '$ProjectID'";
$SQL="Select * From Texts Where TemplateID = '$TemplateID' and TextID = '$Txt[1]'";