God damn Arrays and echo!

Hi,

I'm on the brink of smashing my head against a large rock unless someone can get this script to work. If you manage it, I will be eternally greatful.

Here's the low-down: The script has URLs in an array, named "$linkarray[1]", therefore each URL is "$linkarray[1][$i]". I use preg_match to take the URLs and return with ONLY the domain and extension. EG: "www.example.com/whatever" into "example.com". Here's the code:

function parseDomainName($host)

{

        static $tlds = array('.com', '.net', '.org');

 

        foreach ($tlds as $tld)

       {

                if (preg_match('/^(.*)' . preg_quote($tld) . '$/i', $host, $matches))

                {

                        $name_parts = explode('.', $matches[1]);

                        return array_pop($name_parts) . $tld;

                }

        }

        return false;

}

 

$urls = $linkarray[1];

 

for ($i = 0; $i < count($urls); ++$i)

{

       $url_parts = parse_url($linkarray[1][$i]);

       $domain = parseDomainName($url_parts['host']);

        //echo $urls[0] . "<br />\n";
		//echo $urls[$i]."<br>";
		//echo $url[$i];
		

}

PHP:

Testing this, it returns nothing but the contents of "$linkarray[1]" It seems to me as if the "$url_parts" and "$domain" part isn't being applied. If it was, it would return the contents of "$linkarray[1]" with each single URL converted into the domain and extension. Could someone please tell me what I should be echoing to get the result? I've tried the three above that are commented out, but only one gives a result, just the untouched contents of the "$linkarray[1]".

PLEASE help.

Thank you very much in advance.

 

If all you want to do is pull the domain from the URL, this should do the trick:

#################################################
# extract the domain portion from a given URL
function PullDomain( $url)
{
if(!isset( $url[3]) ) { return ""; }

$url = preg_replace( '!(ftp|http|https):\/\/!', '', $url);

list($url, $junk) = explode( "/", $url, 2);

return $url;
}

Code (markup):

 

foreach($linkarray[1] as $link) {
//use clancey's function
echo PullDomain($link);
}

PHP:

 

Hey Damien,

Thought I would just throw this out there...

// Returns array of vals. Ex: array("www", "example", "com"); 
$host = explode(".", $_SERVER['HTTP_HOST'], 2);

// or to pass in a supplied host
function parseDomainName($host) {
    $pHost = explode(".", $host, 2);
    return $pHost;
}

// In case you want this as well. 
// Returns array of parsed request uri. Ex: array("path" => "/blog")
$uri = parse_url($_SERVER['REQUEST_URI']);

PHP:

You can then print out the array to see what parts you need...

print_r ($host);
print_r (parseDomainName('www.example.com'));
print_r ($uri);

PHP:

I hope this helps you out.

 

Hey,

(This is damien by the way, I had to change to another account)

Thank you SO MUCH guys. It works the closest to what I need. There are only 2 little problems. When I use your code rjb, It shows:

Array ( [0] => "http://www [1] => parkers.co.uk/" )

Code (markup):

For example, how would I stop the first array, array0 from being used? It's created with this line:

print_r (parseDomainName($linkarray[1][$i]));

PHP:

How would I just have [1] of the parsedomainname shown?

Also, the parsing shows URLs with / after the extension, if you could, would you show how I can "cut off" everything after the / of the URL?

thank you eternally